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dimulka [17.4K]
3 years ago
13

Hey~ Please help me figure out this question..I’ll give ya a bonus if you explain ;p

Mathematics
2 answers:
JulijaS [17]3 years ago
6 0
1.9 x 0.5 = 0.95. the answer is 0.95
luda_lava [24]3 years ago
5 0

Answer:

0.95

Step-by-step explanation:

A good way of solving this is to first turn the fraction into a decimal:

1/2 = 50/100 = 0.50 = 0.5

Then you can multiply these values together to get your answer:

1.9 x 0.5 = 0.95

0.95 is your answer

Hope this helps!

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Find two consecutive odd numbers such that the sum of the first number and one-third of the second number is equal to fifty.
Sphinxa [80]

Answer:

37, 39

Step-by-step explanation:

n + 1/3 (n + 2) = 50

Multiply both sides by 3 to cancel out the 1/3:

3n + (n + 2) = 150

Simplify:

4n + 2 = 150

4n = 148

n = 37

n + 2 = 39

8 0
4 years ago
Read 2 more answers
X f(x)<br> -2 -1/200<br> -1 -1/20<br> 0 -1/2<br> 1 -5<br> 2 -50
Hitman42 [59]

9514 1404 393

Answer:

  f(x) = -1/2·10^x

Step-by-step explanation:

The y-intercept is -1/2.

The common ratio is (-1/20)/(-1/200) = 10, so the exponential function can be written as ...

  f(x) = -1/2·10^x

6 0
3 years ago
What comes 10,000 before and 10,000 after this number 52,812?
astraxan [27]

42,812 and 62,812! You just add and subtract 10,000 from 52,812 and you will get the answer! Hope this helps!


8 0
3 years ago
Find the next two terms in the sequence 1/3, 1/9,1/27,1/81....
netineya [11]
1/243

each second number is being multiplied by three

3*3=9

9*3=27

27*3=81

so 81*3=243

243 is the answer
3 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!! WILL GIVE BRAINLIEST
Katyanochek1 [597]

Answer:

equilateral triangle

Step-by-step explanation:

EQUILATERAL ... all three sides are equal length

ISOSCELES ... two sides are equal length

SCALENE ... none of the three sides are equal length

RIGHT ... one of the angles measures 90 degrees

OBTUSE ... one of the angles measures greater than 90 degrees

ACUTE ... all three angles measure less than 90 degrees

4 0
2 years ago
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