All categories

2 years ago

Hey~ Please help me figure out this question..I’ll give ya a bonus if you explain ;p

Mathematics

2 answers:

JulijaS [17]2 years ago

6 0

1.9 x 0.5 = 0.95. the answer is 0.95

luda_lava [24]2 years ago

5 0

Answer:

0.95

Step-by-step explanation:

A good way of solving this is to first turn the fraction into a decimal:

1/2 = 50/100 = 0.50 = 0.5

Then you can multiply these values together to get your answer:

1.9 x 0.5 = 0.95

0.95 is your answer

Hope this helps!

You might be interested in

What is the effect of the b value in an exponential function? y-a*b^x please help me

Margaret [11]

Answer:

Here's li^{}

nk to the answer:

bit.^{}

ly/3a8Nt8n

4 0

3 years ago

Write an equivalent expression for 27x + 18.

Ugo [173]

Answer:

9 (3x+2)

Step-by-step explanation:

27x + 18 = 9 (3x+2)

By simplifying the Given expression you get 9 (3x+2)

and no matter how many times you simplify that expression you always get the expression you started with so in other word their equavalent to each other

Hope this helps

3 0

3 years ago

The larger of two numbers is five more than twice the smaller number. The sum of the two numbers is 38. Find the numbers.

Damm [24]

Answer:

I would set this up as:

let: lesser number = x

greater number = 2x + 5

Restating the word problem:

lesser number + greater number = 38

x + 2x + 5 = 38

Solving: 3x + 5 = 38

- 5 -5

---------------

3x = 33

--- ---

3 3

x = 11

Substitution for the greater number:

2(11) + 5

22 + 5

8 0

3 years ago

Read 2 more answers

If 9x²+Px+25 is a perfect square, then find the value of P

kvv77 [185]

30 is the value of P
Steps:
A perfect square follows the pattern $a^2+2ab+b^2\\\boxed{a=3,b=5}\\\boxed{2ab=30}$

8 0

3 years ago

Read 2 more answers

The physical plant at the main campus of a large state university receives daily requests to replace fluorescent light bulbs. Th

ankoles [38]

We have been given that the distribution of the number of daily requests is bell-shaped and has a mean of 38 and a standard deviation of 6. We are asked to find the approximate percentage of lightbulb replacement requests numbering between 38 and 56.

First of all, we will find z-score corresponding to 38 and 56.

$z=\frac{x-\mu}{\sigma}$

$z=\frac{38-38}{6}=\frac{0}{6}=0$

Now we will find z-score corresponding to 56.

$z=\frac{56-38}{6}=\frac{18}{6}=3$

We know that according to Empirical rule approximately 68% data lies with-in standard deviation of mean, approximately 95% data lies within 2 standard deviation of mean and approximately 99.7% data lies within 3 standard deviation of mean that is $-3\sigma\text{ to }3\sigma$ .

We can see that data point 38 is at mean as it's z-score is 0 and z-score of 56 is 3. This means that 56 is 3 standard deviation above mean.

We know that mean is at center of normal distribution curve. So to find percentage of data points 3 SD above mean, we will divide 99.7% by 2.

$\frac{99.7\%}{2}=49.85\%$

Therefore, approximately $49.85\%$ of lightbulb replacement requests numbering between 38 and 56.

6 0

3 years ago