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3 years ago

Two numbers add to be 5 multiply to be -6

Mathematics

1 answer:

FrozenT [24]3 years ago

3 0

Answer:

-1, 6

Step-by-step explanation:

x + y = 5

xy = -6

Take first equation and rewrite it. y = -x + 5

Then substitute the new equation in the second one.

x(-x + 5) = -6

-x^2 + 5x + 6 = 0

Divide by -1

x^2 - 5x - 6

(x + 1)(x - 6) = 0

x = -1, 6

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Exact = 50 Approximate = 45

Nikitich [7]

Answer:

Approximate of error = 11.11 % (Approx.)

Step-by-step explanation:

Given:

Exact value = 50

Approximate value = 45

Find:

Approximate of error

Computation:

Approximate of error = [(Exact value - Approximate value)/Approximate value]100

Approximate of error = [(50 - 45)/45]100

Approximate of error = [(5)/45]100

Approximate of error = [0.11111]100

Approximate of error = 11.11 % (Approx.)

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2 years ago

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2 years ago

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2 years ago

Convert to factored form y = x² + 6x

steposvetlana [31]

Convert to factored form is:

$y = x(x + 6)$

Solution:

Given that,

$y = x^2 + 6x$

We have to convert to factored form

Factored form means writing terms in multiplication. i.e as a product

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3 years ago

Show that any number of the form ABCABC (e.g. 356356) is divisible by 13.

Shtirlitz [24]

We could write such a number as

$10^5a+10^4b+10^3c+10^2a+10b+c$

$=10^2(10^3+1)a+10(10^3+1)b+(10^3+1)c$

$=(10^3+1)(100a+10b+c)$

$10^3+1=1001=13\cdot77$ so we're done.

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