X^4 + 2x^2 - 24
= (x^2 + 6)(x^2 - 4)
= (x^2 + 6)(x - 2)(x + 2)
x^4 - 9x^2 + 18
= (x^2 - 6)(x^2 - 3)
Answer:
The volume is <em>997.62 cubic units.</em>.
Step-by-step explanation:
We are given the following details:
The pyramid has a regular hexagonal base i.e. each side of hexagon is equal.
Side of hexagonal base, a = 8 units
Altitude of pyramid, h = 18 units
We have to find the volume of pyramid.
Formula:
Where, B is the area of base of pyramid.
h is the height/altitude of pyramid
To calculate B:
Here, base is a hexagon with side 8 units.
Here, a = 8 units
Putting values of B and h in Formula of volume:
Hence, the volume is <em>997.62 cubic units.</em>
28 would be the correct answer to that equation
Answer:
x(15) = 21 lb
Step-by-step explanation:
Rate of change in volume of salt water solution = rate of volume incoming - rate of volume outgoing
dV/dt = 4 - 2 =2gal/min
So, the equation for volume at cetain time t at given conditions and values becomes,
V(t) = 2t + V
V(t) = 2t + 20 gal-------------------euqation (1)
Rate of change in amount of salt = rate of salt in - rate of salt out
dx/dt = {0.5*4} - {[x(t)/V(t)]*2}
dx/dt = 2-2[(x(t))/(2t+20)]
dx/dt = 2-[(x(t))/(v(t))] lb/min
Now, with integrating factor, we get
exp[∫(1/(1+10))dt)] = t+10
the equation becomes
(t + 10)*x' + x = 2*(t+10)
((t+10)*x') = 2*(t+10)
(t+10)*x = t² + 20t + C
As x(0) = 0,
x(t) = (t²+20t)/(t+10)
x(15) = (15²+20*15)/(15+10)
x(15) = 21 lb
Answer: to find volume you need to multiply the L x W x H. The area is something completely different in contrast with the volume.
Step-by-step explanation:
