Answer:
-¹²/₅
Step-by-step explanation:
Let cos a = -⁵/₁₃
Then tan a = sin a/cos a
= [√(1 - cos²a)]/cos a
= {√[1 - (-⁵/₁₃)²]}/(-⁵/₁₃)
= -[√(1 - ²⁵/₁₆₉)] × ¹³/₅
= -[(√(¹⁴⁴/₁₆₉ )] × ¹³/₅
= -¹²/₁₃ × ¹³/₅
= -¹²/₅
tan(arccos (-⁵/₁₃)) = -¹²/₅
The diagram shows the 2nd quadrant of a circle with radius 13, cos a = -⁵/₁₃, and tan a = ¹²/₍₋₅₎ = -¹²/₅.
Answer:
she swam 1500 meters in 1/4 of the time and he swam 750 in half of his time. Hope this helps
Answer:
That would be D.
Step-by-step explanation:
first, turn both to polar form. Then you plot the first one and scale by the second. also, using a Rectangular to Polar calculator, we can see that 2.82 is 2 sqrt 2, so it cannot be A or B. It also can't be C since you graph 3-17i first.
We can set up an equation.
.05 * 2^(n-1)
n being the nth term in the sequence
Plug in and solve.
.05 * 2^(20-1)
.05 * 2^19
.05 * 524, 288
The 20th term would be 262, 144.
