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3 years ago

Calcular los perimetros de las siguientes figuras porfa ayúdenme ya

Mathematics

1 answer:

Basile [38]3 years ago

7 0

Answer:

solo suma todos los valores x+4(3)+(x+x)

en el segundo x+5(2)+x+3(2)

en el tercero x-3+(2x+5)+(2x+5)

y en el cuarto x(3)+(x+4)

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△ABC = △DBC, AB= 10, AC=7 DC= ?

Furkat [3]

Answer:DC=7

Step-by-step explanation:

As it is written △ABC = △DBC. So the corresonding legs (the legs which are equal ) are as follows:

AC=DC AB=DB BC= BC

So DC=7 the same like AC

7 0

3 years ago

Tina wrote the equations 3x - y = 9 and 4x + y + 5, What can Tina conclude about the solution to this system of equations?

Maru [420]

3x - y = 9
4x + y = 5
---------------add
7x = 14
x = 14/7
x = 2

3x - y = 9
3(2) - y = 9
6 - y = 9
-y = 9 - 6
-y = 3
y = -3

C. (2,-3) is a solution to the system of linear equations

4 0

3 years ago

Read 2 more answers

sara buys 3 gallons of juice. she want to fill 1 pint bottles with juice. how many 1 pint bottles can sara completely fill with

Mandarinka [93]

Answer:

So Sara can fill 24 pint bottles completly with 3 gallons of juice.

Step-by-step explanation:

This question can be solved using a rule of three.

Each pint has 0.125 gallons. How many pints are 3 gallons?

1 pint - 0.125 gallons

x pints - 3 gallons

$0.125x = 3$

$x = \frac{3}{0.125}$

$x = 24$

So Sara can fill 24 pint bottles completly with 3 gallons of juice.

8 0

3 years ago

Find dy/dx when r=2 2cos(theta) , then find slope of tengent line at point(4, 2pi)

Korolek [52]

The slope of tangent line at point(4, 2pi) is undefined.

For given question,

We have been given a polar equation r = 2 + 2cos(θ)

We need find dy/dx as well as the slope of tangent line at point(4, 2π).

We know that, for polar equation we use,

x = r cos(θ) and y = r sin(θ)

plug the given value of r into these equations we get:

⇒ x = r cos(θ)

⇒ x = (2 + 2cos(θ) ) × cos(θ)

⇒ x = 2(cos(θ) + cos²(θ))

⇒ x = 2cos(θ) + 2cos²(θ)

Similarly,

⇒ y = r sin(θ)

⇒ y = (2 + 2cos(θ) ) × sin(θ)

⇒ y = 2(sin(θ) + sin(θ)cos(θ))

⇒ y = 2sin(θ) + 2sin(θ)cos(θ)

Now we find derivative of x and y with respect to theta.

$\Rightarrow \frac{dx}{d\theta} =-2sin(\theta)+2(-2cos(\theta)sin(\theta))\\\\\Rightarrow \frac{dx}{d\theta} =-2sin(\theta)-2sin(2\theta)$ .............(1)

Similarly,

$\Rightarrow \frac{dy}{d\theta}=2cos(\theta)+2(cos^2(\theta)-sin^2(\theta))\\\\\Rightarrow \frac{dy}{d\theta}=2cos(\theta)+2(cos(2\theta))$ ..............(2)

Now we find dy/dx

⇒ dy/dx = (dy/dθ) / (dx/dθ)

From (1) and (2),

$\Rightarrow \frac{dy}{dx} =\frac{2cos(\theta)+2cos(2\theta)}{-2sin(\theta)-2sin(2\theta)} \\\\\Rightarrow \frac{dy}{dx} =\frac{2(cos(\theta)+cos(2\theta))}{-2(sin(\theta)+sin(2\theta))}\\\\\Rightarrow \frac{dy}{dx} =-\frac{cos(\theta)+cos(2\theta)}{sin(\theta)+sin(2\theta)}$

We know that The slope of tangent line is given by dy/dx.

So, the slope is: $m =-\frac{cos(\theta)+cos(2\theta)}{sin(\theta)+sin(2\theta)}$

Now we need to find the slope of tangent line at point(4, 2pi)

Substitute θ = 2π in above slope formula.

$\Rightarrow m =-\frac{cos(2\pi)+cos(2\times 2\pi)}{sin(2\pi)+sin(2\times 2\pi)}\\\\\Rightarrow m=-\frac{1+cos(4\pi)}{0+sin(4\pi)}\\\\\Rightarrow m=-\frac{1+cos(4\pi)}{sin(4\pi)}$