Wonderful! You gave us everything we could ever possibly want
to know, except the QUESTION. Fortunately, here at Brainly, we
have five Hogwarts drop-outs who work weekends for us as our
Department of Clairvoyance. When people post an intriguing
question but leave out some important part of it, our D of C can
usually fill in the missing part for us ... especially on weekends.
The question you left out is:
What is the next time that a red bus and a blue bus
will both leave the stadium together, simultaneously
and also both at the same time ?
Since red buses leave every 6 minutes starting at 4:00, and
blue buses leave every 8 minutes starting at 4:00, they both
leave simultaneously and also at the same time at minutes
after 4:00 that are common multiples of 6 and 8.
The least common multiple of 6 and 8 is 24 . After that,
every multiple of 24 is another common multiple of 6 and 8.
24 minutes is 4 red buses and 3 blue buses ... exactly !
A red bus and a blue bus will leave the stadium together at 4:24 .
After that, it will happen again at 24-minute intervals ... at 4:48,
5:12, 5:36, 6:00, . . . etc.
Answer:
D. 5x^2-6/2
Step-by-step explanation:
5x^2-18/6 , 18/6 is 6/2
5x^2-6/2 ,
(1/3) × the cone's volume = The cylinder's volume.
Step-by-step explanation:
Step 1:
The volume of any cone is obtained by multiplying
with π, the square of the radius (
) and the height (
).
So the volume of the cone,
.
Step 2:
The cylinder's volume is nearly the same as the cone but instead by multiplying
we multiply with 1.
So the cylinder's volume is determined by multiplying π with the square of the radius of the cylinder (
) and the height of the cylinder (
).
So the the cone's volume,
.
Step 3:
Now we equate both the volumes to each other.
The cone's volume : The cylinder's volume =
=
.
So if we multiply the cone's volume with
we will get the cylinder's volume with the same dimensions.
Answer:
69.20in
Step-by-step explanation:
Given data
diagonal of the TV d= 55in
Widht of the TV w= 42 in
Hight h= ???
Applying the Pythagoras theorem
d^2= w^2+ h^2
substitute
55^2= 42^2+ h^2
3025= 1764+ h^2
3025+1764= h^2
4789= h^2
h=√4789
h= 69.20
Hence the Heigth is 69.20in