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Dennis_Churaev [7]
2 years ago
10

Tommy must inspect a bridge that goes over a river. He begins 18 feet above water level to inspect the lighting, descends 32 fee

t to inspect the base of the bridge underwater, then descends another 4 feet to check on the concrete anchoring the base. Which best represents Tommy's position with respect to the water level?
Mathematics
2 answers:
Diano4ka-milaya [45]2 years ago
8 0

Answer:

18 - 32 = -14

-14 - 4 = -18

Step-by-step explanation:

Alborosie2 years ago
4 0
Yes i can help what u need yes un sueno moy raro
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What information do you need to find the area of a triangle using trigonometry?
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Formula of the area of triangle 
A=(1/2)a*b*sin(C)
a, b - sides
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8 0
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PLEASE HELP!!!!
emmasim [6.3K]

Answer:

C

Step-by-step explanation:

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4 0
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Write an equation of the hyperbola given that the center is at (2, -3), the vertices are at (2, 3) and (2, - 9), and the foci ar
zavuch27 [327]
Check the picture below.

so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).

because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,

\bf \textit{hyperbolas, vertical traverse axis }
\\\\
\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1
\qquad 
\begin{cases}
center\ ( h, k)\\
vertices\ ( h,  k\pm a)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{ a ^2 + b ^2}\\
asymptotes\quad  y= k\pm \cfrac{a}{b}(x- h)
\end{cases}\\\\
-------------------------------

\bf \begin{cases}
h=2\\
k=-3\\
a=6\\
c=2\sqrt{10}
\end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
c^2=a^2+b^2\implies (2\sqrt{10})^2=6^2+b^2\implies 2^2(\sqrt{10})^2=36+b^2
\\\\\\
4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2
\\\\\\
\sqrt{4}=b\implies 2=b\\\\
-------------------------------\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1

3 0
2 years ago
 m∠A = 42 and m∠C = 57. Find m∠B.<br>A. 81<br><br> B. 99<br><br> C. 132<br><br> D. 147
faltersainse [42]
A.
because the total distance of every triangle 180. Add the two other angles so 42+ 57 =99. Then you have to subtract those two combined angles to find the missing one from the total distance, which is 180. 180-99=81. the answer is A. 81
5 0
3 years ago
help!!! Find x- and y-intercepts. Write ordered pairs representing the points where the line crosses the axes. y=2x+4
zhannawk [14.2K]

y- intercept = (0, 4), x-intercept = (- 2, 0)

to find the intercepts let x = 0 and y = 0 in the equation

x = 0 → y = 0 + 4 =4 ⇒ y-intercept (0, 4)

y = 0 → 2x + 4 = 0 ⇒ x = - 2 ⇒ x- intercept(- 2, 0)


8 0
3 years ago
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