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2 years ago

Someone please help!!!!! WILL MARK BRAINLIEST

Mathematics

1 answer:

adoni [48]2 years ago

3 0

Answer:

y = (1/2)x + 1

Step-by-step explanation:

linear line equation is y = mx + b

Where m is the slope and b is the y-intercept when x is 0.

For m, m is change in y(delta y) over change in x(delta x).

We are given two points: (0,1) and (4,3).

m = (y2 - y1)/(x2 - x1) = (3-1)/(4-0) = 2/4 = 1/2

y = (1/2)x + b

Now plug in (0,1) into above equation to find b value.

1 = (1/2)0 + b => b = 1

Final equation is y = (1/2)x + 1

You might be interested in

4x +6y =0

PSYCHO15rus [73]

Here, x - 2y = 14
x = 14 + 2y

Now, substitute this value into first equation,
4x + 6y = 0
4(14 + 2y) + 6y = 0
56 + 8y + 6y = 0
14y = -56
y = -56/14
y = -4

Substitute it into second equation,
x = 14 + 2(-4)
x = 14 - 8
x = 6

In short, Your Answer would be: (6, -4)

Hope this helps!

4 0

3 years ago

Read 2 more answers

Please help with these questions thank you all so much

Anarel [89]

1.26 A. 2 D. This is a filler lol

8 0

2 years ago

An important tool in archeological research is radiocarbon dating, developed by the American chemist Willard F. Libby.3 This is

Radda [10]

Answer:

Q(t) = Q_o*e^(-0.000120968*t)

Step-by-step explanation:

Given:

- The ODE of the life of Carbon-14:

Q' = -r*Q

- The initial conditions Q(0) = Q_o

- Carbon isotope reaches its half life in t = 5730 yrs

Find:

The expression for Q(t).

Solution:

- Assuming Q(t) satisfies:

Q' = -r*Q

- Separate variables:

dQ / Q = -r .dt

- Integrate both sides:

Ln(Q) = -r*t + C

- Make the relation for Q:

Q = C*e^(-r*t)

- Using initial conditions given:

Q(0) = Q_o

Q_o = C*e^(-r*0)

C = Q_o

- The relation is:

Q(t) = Q_o*e^(-r*t)

- We are also given that the half life of carbon is t = 5730 years:

Q_o / 2 = Q_o*e^(-5730*r)

-Ln(0.5) = 5730*r

r = -Ln(0.5)/5730

r = 0.000120968

- Hence, our expression for Q(t) would be:

Q(t) = Q_o*e^(-0.000120968*t)

7 0

3 years ago

Marcus loves baseball and wants to create a home plate for his house. Marcus needs to calculate the area of the home plate at th

Jobisdone [24]

Answer:

Area of the polygon = 59 in²

Explanation:

From the given diagram, we can note that the given polygon is composed of an upper triangle, a side triangle and a rectangle

Therefore:

Area of polygon =

area of upper triangle + area of side triangle + area of rectangle

1- getting the area of the upper triangle:

We have:

base of triangle = 7 in

height of triangle = 6 in

Therefore:

Area of upper triangle = $\frac{1}{2}*base*height = \frac{1}{2}*7*6=21$ in²

2- getting the area of the side triangle:

We have:

base of triangle = 4 in

height of triangle = 5 in

Therefore:

Area of upper triangle = $\frac{1}{2}*base*height = \frac{1}{2}*4*5=10$ in²

3- getting the area of the rectangle:

We have:

length of rectangle = 7 in

width of rectangle = 4 in

Therefore:

Area of rectangle = length x width = 7 x 4 = 28 in²

4- getting the total area of the polygon:

Area of polygon =

area of upper triangle + area of side triangle + area of rectangle

Therefore:

Area of polygon = 21 + 10 + 28 = 59 in²

Hope this helps :)

4 0

3 years ago

If the line 2x+3y=6 is perpendicular to the line ax+4y=3, then a=?

olga nikolaevna [1]

Answer:3y=−2x+12

y=(−2x+12)/3

y=-2x/3+4

m=-2/3

perpendicular -1/m=3/2

y=mx+c

y=3/2x+12

2y=3x+12

Step-by-step explanation:

8 0

2 years ago

Someone please help!!!!! WILL MARK BRAINLIEST ​

Someone please help!!!!! WILL MARK BRAINLIEST