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3 years ago

Without graphing, decide whether the following system of linear

Mathematics

1 answer:

zhuklara [117]3 years ago

6 0

There is no solution

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For f (x) - 4x +1 and g(x) = ? -5, find (fºg)(4).

Alona [7]

$(f\circ g)(x)=f(g(x))=4(x^2-5)+1=4x^2-19$

$(f\circ g)(4)=4\cdot4^2-19=64-19=\boxed{45}$

Hope this helps.

5 0

3 years ago

Help me plz i’ll give extra points

Anon25 [30]

B,D

(1,3),(2,5),(3,7)(4,9)
(1,3),(2,3),3,3)(4,3)

I think that’s it

8 0

3 years ago

A company's revenue (in dollars) can be modeled by the function

Tju [1.3M]

R(p) = -15p² + 200p + 10,000
To find the maximum of the function, we take the first derivative and equate to 0:

R'(p) = -30p + 200
0 = -30p + 200
p = 6.67

A price of $6.67 will maximize revenue.

6 0

4 years ago

PLEASE HELP ME I BEG YOU

Marat540 [252]

1- False

2- False

3- False

4-False

5 0

3 years ago

A rectangular school banner has a length of 36 inches and a width of 52 inches. A sign is made that is similar to the school ban

zalisa [80]

Answer:

4212 : 1573 is the ratio.

Step-by-step explanation:

Given:

Length of rectangular school banner is 36 inches and width is 52 inches.

And, the sign made is similar to banner.

The sign's length is 22 inches.

Now, we have to find the ratio of the area of the banner to the area of the sign.

So, we have dimensions of rectangular school banner:

Length = 36 inches.

Width = 52 inches.

But, we have only length of sign:

Length = 22 inches.

Now, we have to find the width of sign by using cross multiplication method:

Let the width of sign be $x.$

As, sign is similar to banner.

So, if 36 inches is equivalent to 52 inches.

Then, 22 inches is equivalent to $x.$

$\frac{36}{52} =\frac{22}{x}$

By cross multiplying we get:

$36x=1144$

Dividing both sides by 36 we get:

$x=31\frac{7}{9} .$

Hence, the width of sign is $31\frac{7}{9}$ inches.

Now, we find the area of banner and the area of sign by putting formula:

Area of banner = length × width.

$Area\ of\ banner=36\times 52$

$Area\ of\ banner=1872\ square\ inches.$

Now, area of sign:

$Area\ of\ sign=length\times width\\\\Area\ of\ sign=22\times 31\frac{7}{9} \\\\Area\ of\ sign=22\times \frac{286}{9} \\\\Area\ of\ sign=\frac{6292}{9} \ square\ inches.$

Now, to get the ratio of the area of the school banner to the area of the sign:

$1872:\frac{6292}{9}$

$=\frac{1872}{\frac{6292}{9} } \\\\=\frac{16848}{6292}$

On simplifying we get:

$=\frac{4212}{1573}$

$=4212:1573.$

Therefore, the ratio of the area of the school banner to the area of the sign is 4212:1573.

8 0

3 years ago