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dsp73
3 years ago
8

Help Me Please!!!!!!!!!!!

Mathematics
1 answer:
DaniilM [7]3 years ago
6 0

Answer:

Have a good day

Step-by-step explanation: and so have a good day

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I hope this helps you




2x and 8x+40 complementary angles

their sum is 180



2x+8x+40=180


10x=140


x=14
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Solve for y.<br> y+9=7<br><br> Any help
liberstina [14]

Answer:

-2

Step-by-step explanation:

7-9=-2 hope this helps

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45.15 divided by 21 is 2.15. Hope it helps!!
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What is the solution to the system of equations?
MatroZZZ [7]

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5 0
4 years ago
The water from a fire hose follows a path described by y equals 2.0 plus 0.9 x minus 0.10 x squared ​(units are in​ meters). If
Alecsey [184]

Answer:

The resultant velocity is 12.21 m/s.

Step-by-step explanation:

We are given that the water from a fire hose follows a path described by y equals 2.0 plus 0.9 x minus 0.10 x squared ​(units are in​ meters).

Also, v Subscript x is constant at 10.0 ​m/s.

The water from a fire hose follows a path described by the following equation below;

y=2.0 + 0.9x-0.10x^{2}

The velocity of the x component is constant at =  v_x=10.0 \text{ m/s}

and the point at which resultant velocity has to be calculated is (9.0,2.0).

Let the velocity of x and y component be represented as;

v_x=\frac{dx}{dt} \text{   and    }   v_y=\frac{dy}{dt}

Now, differentiating the above equation with respect to t, we get;

y=2.0 + 0.9x-0.10x^{2}

\frac{dy}{dt} =0 + 0.9\frac{dx}{dt} -(0.10\times 2)\frac{dx}{dt}

\frac{dy}{dt} = 0.9\frac{dx}{dt} -0.2\frac{dx}{dt}

v_y = 0.9v_x -0.2v_x

v_y = 0.7v_x

Now, putting v_x=10.0 \text{ m/s} in the above equation;

v_y = 0.7 \times 10.0 = 7 m/s

Now, the resultant velocity is given by = v=\sqrt{v_x^{2}+v_y^{2}  }

                            v=\sqrt{10^{2}+7^{2}  }

                               = \sqrt{149} = 12.21 m/s

5 0
3 years ago
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