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Elenna [48]
4 years ago
9

Find the compound amount of 16100 for 4 years and 6 months and 10% compounded quarterly

Mathematics
1 answer:
Marina86 [1]4 years ago
3 0

Answer:

25110.51

Step-by-step explanation:

A = P(1 + r/n)^(nt)

A = final amount

P = initial principal balance

r = interest rate

n = number of times interest applied per time period

t = number of time periods elapsed

A = 16100(1+.1/4)^(4*4.5) = 25110.51

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I need help, has to be turned in tomorrow morning!
Kipish [7]

Answer: (5,5)

Step by step explanation:

We have the two equations

-7x + y = -30 and y = 2x - 5

one of the equations "define" y therefore we can plug the value of y into the other equation and solve for x

-7x + y = -30

plug in y = 2x - 5

-7x + 2x - 5 = -30

combine like terms

-5x - 5 = -30

add 5 to both sides

-5x = -25

divide both sides by -5

-5x/-5 = x and -25/-5 = 5

we're left with x = 5

we now plug in the value of x into one of the equations and solve for y

2x - 5 = y

x = 5

2(5) - 5 = y

multiply 2 and 5

10 - 5 = y

subtract

y = 5

the solution is (5,5)

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Graph ƒ(x) = -1/2x. Click on the graph until the graph of ƒ(x) = -1/2x appears.
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Given that 2x + 3 > 9, the range of values of x is
guajiro [1.7K]

Answer:

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CON PROCESOS POR FAVOR
labwork [276]

Answer:

\dfrac{149}{40}

\dfrac{38}{15}

Step-by-step explanation:

(\dfrac{7}{8} + \dfrac{4}{5}) - (\dfrac{9}{20} + \dfrac{-5}{2}) =

= (\dfrac{7}{8} \times \dfrac{5}{5} + \dfrac{4}{5} \times \dfrac{8}{8}) - (\dfrac{9}{20} + \dfrac{-5}{2} \times \dfrac{10}{10})

= (\dfrac{35}{40} + \dfrac{32}{40}) - (\dfrac{9}{20} + \dfrac{-50}{20})

= \dfrac{67}{40} - (-\dfrac{41}{20})

= \dfrac{67}{40} + \dfrac{41}{20} \times \dfrac{2}{2}

= \dfrac{67}{40} + \dfrac{82}{40}

= \dfrac{149}{40}

(-\dfrac{6}{4} + \dfrac{3}{2}) + (\dfrac{6}{5} + \dfrac{4}{3}) =

= (-\dfrac{3}{2} + \dfrac{3}{2})+ (\dfrac{6}{5} \times \dfrac{3}{3} + \dfrac{4}{3} \times \dfrac{5}{5})

= 0 + \dfrac{18}{15} + \dfrac{20}{15}

= \dfrac{38}{15}

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2 years ago
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