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Elenna [48]
3 years ago
9

Find the compound amount of 16100 for 4 years and 6 months and 10% compounded quarterly

Mathematics
1 answer:
Marina86 [1]3 years ago
3 0

Answer:

25110.51

Step-by-step explanation:

A = P(1 + r/n)^(nt)

A = final amount

P = initial principal balance

r = interest rate

n = number of times interest applied per time period

t = number of time periods elapsed

A = 16100(1+.1/4)^(4*4.5) = 25110.51

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In a sample of digits(0,1,2,3,4,5,6,7,8,9,) what is the probability that a digit is 7 or greater
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\frac{3}{10}

Step-by-step explanation:

There are 10 numbers in total. Only three are 7 or greater: 7, 8, 9.

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3 years ago
Assume that a simple random sample has been selected from a normally distributed population. Find the test statistic t.
lawyer [7]

Using the t-distribution, it is found that the p-value of the test is 0.007.

At the null hypothesis, it is <u>tested if the mean lifetime is not greater than 220,000 miles</u>, that is:

H_0: \mu \leq 220000

At the alternative hypothesis, it is <u>tested if the mean lifetime is greater than 220,000 miles</u>, that is:

H_1: \mu > 220000.

We have the <u>standard deviation for the sample</u>, thus, the t-distribution is used. The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
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For this problem:

\overline{x} = 226450, \mu = 220000, s = 11500, n = 23

Then, the value of the test statistic is:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{226450 - 220000}{\frac{11500}{\sqrt{23}}}

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Using a t-distribution calculator, the p-value of the test is of 0.007.

A similar problem is given at brainly.com/question/13873630

8 0
2 years ago
What is the answer? Please help
goblinko [34]

Answer:

A

Step-by-step explanation:

One and three hundred and four thousand

1+                             3/100+          4/1000

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3 years ago
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