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Varvara68 [4.7K]
3 years ago
13

Q1: Using the known values of the mass of the earth and the radius of the earth, calculate the

Physics
1 answer:
kupik [55]3 years ago
3 0

Answer:

m g = G * m * M / R^2      force of attraction

g = G * M / R^2

g = 6.67E-11 * 5.96E24 / (6.37E6)^2

g = 6.67 * 5.96 / 6.37^2 * 10^1

g = .98 * 10 = 9.8 m/s^2

Q2.

d g = G M * (-2 R^-3 dR ) = -2 G M / R^3       (very small where dR = 1)

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Answer:

6.75\mu C/m^2

Explanation:

We are given that

Diameter,d=1\mu m=1\time 10^{-6} m

1\mu m=10^{-6} m

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Total number of electrons,n=39

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Total charge=q=ne=39\times 1.6\times 10^{-19}=62.4\times 10^{-19} C

Distance,s=2mm=2\times 10^{-3} m

Mass =density\times volume=900\times \frac{4}{3}\pi r^3=900\times \frac{4}{3}\pi(0.5\times 10^{-6})^3=4.7\times 10^{-16} kg

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Final speed,v=4.5 m/s

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Gravity is generally measured in terms of acceleration due to gravity, denoted as g. For Earth it is, 9.8 m/s². And for moon, it is about 1.62 m/s².

On Earth, your weight is 70 kg = W

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70 = mass x 9.8

Your mass is 70/ 9.8

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Hence, your weight on the surface of the moon is just 11.56 kg.

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Answer:

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