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Sophie [7]
3 years ago
13

I have 5 digits.My 9 is worth 10000. my 2 is worth 2 thousand one of my 7s is worth 70. the other is worth 10 times as much. my

other digits is a 6
Mathematics
1 answer:
liberstina [14]3 years ago
5 0

Answer:

92776

Step-by-step explanation:

FIrst multiply:

9*10000= 90000

2*1000=2000

70*10= 700

Then add:

90000+2000+700+70(already given)+6(already given)= 92776

Hope this helps! :)

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iVinArrow [24]

Answer:

The answer would be letter J

5 0
3 years ago
Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8
Delvig [45]
We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69

Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22

Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34
Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86

Thus the 98% confidence interval will be (105.34, 141.86)


Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.
3 0
3 years ago
I’ll give brainliest HELO ASAP PLZ!!
Helen [10]

Answer:

a

Step-by-step explanation:

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2 years ago
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Answer:

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Step-by-step explanation:

4 0
2 years ago
Clare and Noah play a game in which they earn the same number of points for each
Korvikt [17]

6x+3y=6  and 8x+9y= -22  describes the outcomes of Clare and Noah.

Step-by-step explanation:

Let,

x represents the number of points for a goal.

y represents the number of points for a penalty.

Therefore,

6 goals = 6x

3 penalties = 3y

8 goals = 8x

9 penalties = 9y

According to given statment;

6x+3y=6    Eqn 1

8x+9y= -22   Eqn 2

6x+3y=6  and 8x+9y= -22  describes the outcomes of Clare and Noah.

Keywords: linear equation, variables

Learn more about linear equations at:

  • brainly.com/question/13218251
  • brainly.com/question/1332667

#LearnwithBrainly

5 0
3 years ago
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