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Sophie [7]
3 years ago
13

I have 5 digits.My 9 is worth 10000. my 2 is worth 2 thousand one of my 7s is worth 70. the other is worth 10 times as much. my

other digits is a 6
Mathematics
1 answer:
liberstina [14]3 years ago
5 0

Answer:

92776

Step-by-step explanation:

FIrst multiply:

9*10000= 90000

2*1000=2000

70*10= 700

Then add:

90000+2000+700+70(already given)+6(already given)= 92776

Hope this helps! :)

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CAN SOMEONE PLEASE HELP ME ASAP PLEASEE ANYBODY LITERALLY ANYONE OUT THERE PLEASE
marin [14]

Answer:

Y1 is parallel to Y2 and L1 to L2.

Step-by-step explanation:

A line is 180°. To find the degree the angles I subtracted 117 and 63 by 180 to find thair respective angles. (Also 117+63 equil 180) meaning that the Y's and L's are parallel to each other.

6 0
3 years ago
What are the coordinates of the endpoints A'B after a reflection of segment AB over the line y = - x?
kupik [55]

Answer:

by reflection, if you mean swapped, then the answers are A'(1,-6) and B'(4,2)

i hope these are the answers you are looking for

Step-by-step explanation:

6 0
3 years ago
Can someone please help me???
olganol [36]

Answer:

1. 60000.12

2. 54000.15

3. 9600.48

4. 3840.48

Step-by-step explanation:

I really hope this helps and may I receive brainliest please

7 0
3 years ago
When finding the difference between 2.4 and a number, the answer is 1.57. What number should go in the box to complete the subtr
Airida [17]

Answer:

8

Step-by-step explanation:

2.4 - 1.57 = 0.83

4 0
2 years ago
Find equations of the tangent plane and the normal line to the given surface at the specified point. x + y + z = 8exyz, (0, 0, 8
Dima020 [189]

Let f(x,y,z)=x+y+z-8e^{xyz}. The tangent plane to the surface at (0, 0, 8) is

\nabla f(0,0,8)\cdot(x,y,z-8)=0

The gradient is

\nabla f(x,y,z)=\left(1-8yze^{xyz},1-8xze^{xyz},1-8xye^{xyz}\right)

so the tangent plane's equation is

(1,1,1)\cdot(x,y,z-8)=0\implies x+y+(z-8)=0\implies x+y+z=8

The normal vector to the plane at (0, 0, 8) is the same as the gradient of the surface at this point, (1, 1, 1). We can get all points along the line containing this vector by scaling the vector by t, then ensure it passes through (0, 0, 8) by translating the line so that it does. Then the line has parametric equation

(1,1,1)t+(0,0,8)=(t,t,t+8)

or x(t)=t, y(t)=t, and z(t)=t+8.

(See the attached plot; the given surface is orange, (0, 0, 8) is the black point, the tangent plane is blue, and the red line is the normal at this point)

4 0
3 years ago
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