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2 years ago

2^8 * 2^9* 4 = ? Help a brotha out please

Mathematics

1 answer:

BabaBlast [244]2 years ago

3 0

Answer:

524,288

Step-by-step explanation:

2^8 * 2^9* 4

2 to the 8th power is 256

2 to the power of 9 is 512

256 x 512 x 4= 524,288

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Ben and Josh went to the roof of their 40-foot tall high school to throw their math books offthe edge.The initial velocity of Be

Taya2010 [7]

Answer

Josh's textbook reached the ground first

Josh's textbook reached the ground first by a difference of $t=0.6482$

Step-by-step explanation:

Before we proceed let us re write correctly the height equation which in correct form reads:

$h(t)=-16t^2 +v_{o}t+s$ Eqn(1).

Where:

$h(t)$ : is the height range as a function of time

$v_{o}$ : is the initial velocity

$s$ : is the initial heightin feet and is given as 40 feet, thus Eqn(1). becomes:

$h(t)=-16t^2 + v_{o}t + 40$ Eqn(2).

Now let us use the given information and set up our equations for Ben and Josh.

Ben:

We know that $v_{o}=60ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+60t+40$ Eqn.(3)

Josh:

We know that $v_{o}=48ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+48t+40$ Eqn. (4).

Now since we want to find whose textbook reaches the ground first and by how many seconds we need to solve each equation (i.e. Eqns. (3) and (4)) at $h(t)=0$ . Now since both are quadratic equations we will solve one showing the full method which can be repeated for the other one.

Thus we have for Ben, Eqn. (3) gives:

$h(t)=0-16t^2+60t+40=0$

Using the quadratic expression to find the roots of the quadratic we have:

$t_{1,2}=\frac{-b+/-\sqrt{b^2-4ac} }{2a} \\t_{1,2}=\frac{-60+/-\sqrt{60^2-4(-16)(40)} }{2(-16)} \\t_{1,2}=\frac{-60+/-\sqrt{6160} }{-32} \\t_{1,2}=\frac{15+/-\sqrt{385} }{8}\\\\t_{1}=4.3276 sec\\t_{2}=-0.5776 sec$

Since time can only be positive we reject the $t_{2}$ solution and we keep that Ben's book took $t=4.3276$ seconds to reach the ground.

Similarly solving for Josh we obtain

$t_{1}=3.6794sec\\t_{2}=-0.6794sec$

Thus again we reject the negative and keep the positive solution, so Josh's book took $t=3.6794$ seconds to reach the ground.

Then we can find the difference between Ben and Josh times as

$t_{Ben}-t_{Josh}= 4.3276 - 3.6794 = 0.6482$

So to answer the original question:

Whose textbook reaches the ground first and by how many seconds?

Josh's textbook reached the ground first
Josh's textbook reached the ground first by a difference of $t=0.6482$

3 0

3 years ago

Add or substract the linear expression.

STatiana [176]

Answer:

-7x - 6

Step-by-step explanation:

Distribute

(−2+5)−1(6+4)+(−7)

(−2+5)−6−4+(−7)

Eliminate redundant parentheses

(−2+5)−6−4+(−7)

−2+5−6−4+−7

Add the numbers

−2+5−6−4+−7

−2−6−6+

Combine like terms

−2−6−6+

Answer:

−7−6

4 0

3 years ago

Expand the following

Whitepunk [10]

Answer:

Please complete the question..

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

What is first coordinite

finlep [7]

Answer:

with the information you have given, the first coordinate is this:

Step-by-step explanation:

A first coordinate is on a graph, and it is the first dot, or coordinate set on the plane.

~Ren

5 0

2 years ago

30 points 1 question PLEASE HELP ME OUT I REALLY NEED IT

Pachacha [2.7K]

Answer:

p(-5/3) ≠ 0 So, (3 x +5) is NOT A FACTOR of p(x)

Step-by-step explanation:

Here, the given function is $p(x)=3x^5+2x^2 - 5$

Now, the given root of the function is ( 3x +5)

Now, if ( 3 x + 5) = 0,

we get x = - 5/3

So, the zero of the given polynomial is x = -5/3

Then, x = -5/3, p(x) =0 ⇒ ( 3 x + 5) is a FACTOR of p(x)

Now, let us find the value of function at x = -5/3

Substitute x = -5/3 in the given function p(x), we get:

$p(x)=3x^5+2x^2 - 5 \implies p(\frac{-5}{3}) = 3(\frac{-5}{3})^5 + 2(\frac{-5}{3})^2 - 5\\= 3(\frac{-3,125}{243}) + 2(\frac{25}{9}) - 5\\= (\frac{-3,125}{81}) + (\frac{50}{9}) - 5\\= -38.580 + 5.56 - 5 = -38.02\\\implies p(\frac{-5}{3}) = -38.02$

Now, as p(-5/3) ≠ 0 So, (3x +5) is NOT A FACTOR of p(x)

6 0

3 years ago