X-doubling periods
Y-height of bamboo
Y=ab^x
1) make a table of values
X Y
1 5
2 10
3 20
2) write equations and substitute
5=ab^1 —> a=5/b^1 —> a=5/b
10=ab^2
Substitute into second equation
10=(5/b)*b^2
10=5b^2/b
10=5b
b=2
Substitute back in
b=2
10=a*2^2
10=4a
a=5/2
End equation:
Y=5/2*2^x
Answer:
A. 30
Step-by-step explanation:
Because it showed up the most
Answer:
Step-by-step explanation:
Answer:
Let the distance of school and house is x k m
Then time taken at speed 2.5 km\hr=
2.5
x
hr
And time taken at speed 4 km\hr=
4
x
hr
∴
2.5
x
−
4
x
=
60
12
⇒
10
4x−2.5x
=
5
1
⇒x=3 km
Then the distance of school and house is 3 k m
may this help you
Hey there!!
Let's take the two numbers as 'x' and 'y'
The sum of these two numbers is 36.
... x + y = 36
Twice the first number minus the second is 6.
... 2x - y = 6
Now, we have two equations.
_______________________________________________________
... x + y = 36
... 2x - y = 6
Now, let's add both the equations.
... 3x = 42
Divide each side by 3.
... x = 42 / 3
... x = 14
<em>Hence, the first number is'14'. </em>
We know the sum of both the numbers is 36.
... x + y = 36
... 14 + y = 36
Subtract 14 on both sides.
... y = 36-14
... y = 22
<em>Hence, the second number is 22. </em>
<em>The numbers are 14 and 22. </em>
Hope my answer helps!!
