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attashe74 [19]
3 years ago
13

How many 7s are in 1 to 1000​

Mathematics
2 answers:
yuradex [85]3 years ago
7 0

Answer:5

Step-by-step explanation:

I think 5

miskamm [114]3 years ago
4 0

Answer:

Number 7 will appear 11 times in 1000

(hope this helps can I pls have brainlist (crown) ☺️)

Step-by-step explanation:

7 does not occur in 1000. So we have to count the number of times it appears between 1 and 999. Any number between 1 and 999 can be expressed in the form of xyz where 0 < x, y, z < 9. You have 1 × 9 × 9 = 81 such numbers.

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Step-by-step explanation:

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1 year ago
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How do I solve 2cos(x)=2sin(2x)
Vedmedyk [2.9K]
2cosx=2sin2x. Sin2x is an identity for 2sinxcos. So 2[2sinxcosx] gives you 4sinxcosx. 2cosx=4sinxcosx. Divide 2cosx on both sides and gives you 2sinx=0 and divide again, sinx=0. Sinx is 0 at 0 and 360 degrees, or pi and 2pi. So thats what x would be. 0,360,pi,2pi.
4 0
3 years ago
A parabola can be drawn given a focus of
Volgvan

Answer:

y=-\frac{1}{4}(x-2)^{2}+9

Step-by-step explanation:

Any point on a given parabola is equidistant from focus and directrix.

Given:

Focus of the parabola is at (2,8).

Directrix of the parabola is y=10.

Let (x,y) be any point on the parabola. Then, from the definition of a parabola,

Distance of (x,y) from focus = Distance of (x,y) from directrix.

Therefore,

\sqrt{(x-2)^{2}+(y-8)^{2}}=|y-10|

Squaring both sides, we get

(x-2)^{2}+(y-8)^{2}=(y-10)^{2}\\(x-2)^{2}=(y-10)^{2}-(y-8)^{2}\\(x-2)^{2}=(y-10+y-8)(y-10-(y-8))...............[\because a^{2}-b^{2}=(a+b)(a-b)]\\(x-2)^{2}=(2y-18)(y-10-y+8)\\(x-2)^{2}=2(y-9)(-2)\\(x-2)^{2}=-4(y-9)\\y-9=-\frac{1}{4}(x-2)^{2}\\y=-\frac{1}{4}(x-2)^{2}+9

Hence, the equation of the parabola is y=-\frac{1}{4}(x-2)^{2}+9.

4 0
3 years ago
The area of a rhombus is 72 m2. One<br> diagonal is 18m. Find the other diagonal.
miskamm [114]

Answer:

Other diagonal is 8 m

Step-by-step explanation:

area of rhombus = 72 m²

½ × diagonal 1 × diagonal 2 = 72

½ × 18 × d2 = 72

9 × d2 = 72

d2 = 72/9

d2 = 8

7 0
1 year ago
What are the ordered pairs of the
OlgaM077 [116]

Answer:

The two points solutions to the system of equations are: (2, 3) and (-1,6)

Step-by-step explanation:

These system of equations consists of a parabola and a line. We need to find the points at which they intersect:

x^2-2x+3=-x+5\\x^2-2x+x+3-5=0\\x^2-x-2=0\\(x-2)(x+1)=0

Since we were able to factor out the quadratic expression, we can say that the x-values solution of the system are:

x = 2 and x = -1

Now, the associated y values we can get using either of the original equations for the system. We pick to use the linear equation for example:

when x = 2 then  y=-(2)+5=3

when x= -1  then  y=-(-1)+5=6

Then the two points solutions to the system of equations are: (2, 3) and (-1,6)

6 0
3 years ago
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