All categories

3 years ago

Does anyone know the answer?

Mathematics

1 answer:

azamat3 years ago

6 0

Answer:

1=163 degrees

2=×=10 degrees

3=×=3

Step-by-step explanation:

54x+1+9x-10=180 we are using this expression because alternate angles add up to 180 degrees

54x+9x+1-10=180

63x-9=180

63×=180+9

63×=189

63×÷63×=189÷63×

X=3

Angle in bold print is (54x+1)

54×3=162

162+1=163 degrees

No.2 Find x

7x+35+x+65 =180

7x+x+35×65=180

8x+100=180

8x=180-100

8x=80

8x÷8x=80÷8

X=10 degrees

No.3 Find x

54x+1+9x-10=180

54x+9x+1-10=180

63x-9=180

63x=180+9

63x=189

63x÷63x=189÷63

X=3

I hope I was of help

You might be interested in

Please help asap. Thank you so much! Question 1/7

solniwko [45]

What class is for ? If you tell me I could take out my notes

5 0

2 years ago

Read 2 more answers

WILL MARK AS BRAINIEST AND 35 POINTS

Sauron [17]

Answer: The answer is 11! I hope this helps! :)

Step-by-step explanation:

8 0

3 years ago

Anyone know the answer to this algebra problem?

ikadub [295]

Answer: $\bold{a=1\qquad b=\dfrac{1}{16}\qquad c=\dfrac{1}{64}\qquad d=1\qquad e=\dfrac{4}{9}\qquad f=\dfrac{16}{81}}$

<u>Step-by-step explanation:</u>

$\begin{array}{c|l}\underline{\quad x\quad}&\underline{\quad 4^{-x}\qquad \qquad}\\-1&4^{-(-1)}=4^1=4\\\\0&4^{-(0)}=4^0=1\\\\2&4^{-(2)}=\dfrac{1}{4^2}=\dfrac{1}{16}\\\\4&4^{-(4)}=\dfrac{1}{4^4}=\dfrac{1}{64}\end{array}$

$\begin{array}{c|l}\underline{\quad \bigg x \quad}&\underline{\quad \bigg(\dfrac{2}{3}\bigg)^x\qquad \qquad}\\\\-1&\bigg(\dfrac{2}{3}\bigg)^{-1}=\dfrac{3}{2}\\\\0&\bigg(\dfrac{2}{3}\bigg)^{0}=1\\\\2&\bigg(\dfrac{2}{3}\bigg)^{2}=\dfrac{2^2}{3^2}=\dfrac{4}{9}\\\\4&\bigg(\dfrac{2}{3}\bigg)^{4}=\dfrac{2^4}{3^4}=\dfrac{16}{81}\end{array}$

3 0

3 years ago

zheka24 [161]

The number of ratios from students to adults would be a/s

5 0

3 years ago

Multiply and combine like terms. Use^for exponents. (2x-6) (3x-2)<br>

Georgia [21]

Answer:

Expand the polynomial using the FOIL method.

6x2−22x+12

Step-by-step explanation:

5 0

3 years ago