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Goryan [66]
3 years ago
5

Write three numbers greater than 20 that have 9 as factor

Mathematics
2 answers:
SpyIntel [72]3 years ago
8 0
9 × 3 = 27, 9 × 3 = 36, 9 × 5 = 45
DiKsa [7]3 years ago
7 0
54, 63, and 72 could work :)
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What’s the answer ???
prisoha [69]

Answer:

Step-by-step explanation:

-9/2

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3 years ago
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Literal Equations.
Julli [10]

1) g=6x

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3 0
3 years ago
10 = n +19<br> Inverse operation<br> Answer: 9=n
pishuonlain [190]

Answer:

n=-9

Step-by-step explanation:

subtract 19 to both sides

19-19=0

10-19=(-9)

n=-9

to verify add 19+(-9)=10

hope this helps :3

if it did pls mark brainliest

7 0
3 years ago
Read 2 more answers
What shows a perfect square trinomial?
e-lub [12.9K]

Answer:

The answer is c. 16x2 + 24xy + 9y2.

Step-by-step explanation:


3 0
3 years ago
la spent her whole allowance of $2.00, plus the 16¢ she had left over from last week, onbubble gum. If the pieces of gum had bee
nasty-shy [4]
Let the number of pieces of gum be g and the cost of each piece be c.
gc=2.16. Also, (g+3)(c-0.01)=2.16.
So gc=(g+3)(c-0.01)=gc-0.01g+3c-0.03.
And -0.01g+3c=0.03 and c=2.16/g. -0.01g+6.48/g=0.03.
-0.01g²+6.48=0.03g; 0.01g²+0.03g-6.48=0 which can be more conveniently written:
g²+3g-648=0=(g+27)(g-24) so g=24, the number of pieces she actually had.
CHECK The cost of the gum, c=2.16/24=9 cents.
A penny cheaper makes the gum 8 cents a piece and she could have bought 27 pieces instead of 24.
5 0
3 years ago
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