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Liono4ka [1.6K]
3 years ago
12

Question 8 I need help

Chemistry
1 answer:
Vedmedyk [2.9K]3 years ago
4 0

Answer:A

Explanation: Since the boiling point is 212. As salt keeps getting added the boiling temperature keeps going up. Meaning it will boil at a high temp.

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Name the following compound: CH₂-C- CH₂-CH₂-CH₂-C - H butanal O2-butanol O propyl hydrogen ether 1-propanone​
bulgar [2K]

Answer:

butanal

Explanation:

It's not 1-propanone because otherwise you have OH bonded to C not O and H bonded to C separately. 2-butanol means that the O and H would be bonded to a different C atom, and it's not propyl hydrogen ether because the O would be in the chain of bonded Cs.
Hope this helps :)

6 0
2 years ago
Please help me, Thank you!
Phantasy [73]

Answer:

2

Explanation:

The atom shown in the image has 2 core electrons.

Electrons are the negatively charged particles within an atom. Therefore the total number of electrons surrounding the nucleus in the given specie is 7.

 So;

   We have 2 core electrons

   And 5 valence electrons

The core electrons are the inner orbital electrons.

The valence electrons are the outermost electrons.

3 0
3 years ago
Biological membranes are present in all cells, and they make up the endomembrane system of eukaryotic cells. Among other functio
docker41 [41]

Answer:

The correct option for question 1 would be:

a bilayer containing lipids with hydrophilic head groups pointing inward and hydrophobic tail groups facing the solvent (extracellular fluid and cytosol).

The correct option for question number two would be: proteins.

Explanation:

The membranes present phospholipids that act as selective barriers between the intracellular and extracellular space, allowing an internal balance in relation to the external one.

Its conformation is mostly phospholipids, fatty acids, proteins (from transmembrane to intermembrane or external)

5 0
3 years ago
An unknown compound contains only C , H , and O . Combustion of 5.60 g of this compound produced 13.7 g CO2 and 5.60 g H2O . Wha
son4ous [18]

Answer:

Empirical formula of compound  is C₄H₈O

Explanation:

Given data:

Mass of compound = 5.60 g

Mass of CO₂ = 13.7 g

Mass of H₂O = 5.60 g

Empirical formula of compound = ?

Solution:

Percentage of C:

13.7 g/5.60 g × 12/44× 100

2.45×0.273× 100 = 66.9%

Percentage of H:

5.60 g/ 5.60 g × 2.016/18 × 100

11.2%

Percentage of O:

(66.9% + 11.2%) - 100 = 21.9%

Grams atom of  C , H, O

66.9/12 = 5.6

11.2 / 1.008 = 11.11

21.9 / 16 = 1.4

Atomic ratio:

           C                 :               H           :              O

           5.6/1.4         :            11.11/1.4    :            1.4/1.4

              4                :               8            :               1

Empirical formula:

C₄H₈O

7 0
4 years ago
You have an unknown quantity of oxygen at a pressure of 2.2 atam, a volume of 21 liters and a temperature of 87 Celsius. How man
laila [671]

<span>Let's assume that the oxygen gas has ideal gas behavior. 
Then we can use ideal gas formula,
      PV = nRT</span>


Where, P is the pressure of the gas (Pa), V is the volume of the gas (m³), n is the number of moles of gas (mol), R is the universal gas constant ( 8.314 J mol⁻¹ K⁻¹) and T is temperature in Kelvin.

<span>
P = 2.2 atm = 222915 Pa
V = 21 L = 21 x 10</span>⁻³ m³

n = ?

R = 8.314 J mol⁻¹ K⁻¹

<span> T = 87 °C = 360 K

By substitution,
</span>222915 Pa x 21 x 10⁻³ m³ = n x 8.314 J mol⁻¹ K⁻<span>¹ x 360 K
                                       n = 1.56</span><span> mol</span>

<span>
Hence, 1.56 moles of the oxygen gas are </span><span>left for you to breath.</span><span>
</span>
6 0
3 years ago
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