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tatiyna
2 years ago
13

Name the following compound: CH₂-C- CH₂-CH₂-CH₂-C - H butanal O2-butanol O propyl hydrogen ether 1-propanone​

Chemistry
1 answer:
bulgar [2K]2 years ago
6 0

Answer:

butanal

Explanation:

It's not 1-propanone because otherwise you have OH bonded to C not O and H bonded to C separately. 2-butanol means that the O and H would be bonded to a different C atom, and it's not propyl hydrogen ether because the O would be in the chain of bonded Cs.
Hope this helps :)

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One of the hopes for solving the world's energy problem is
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Answer:

2.803013439419911 × 10⁻¹² J

Explanation:

Mass defect = mass of reactant - mass of product

(2.0140 + 3.01605) - (4.002603 + 1.008665)

5.03005 - 5.011268 = 0.018782 amu

mass in Kg = mass (amu) × 1.66053892173 × 10⁻²⁷ kg

mass in kg = 0.018782 × 1.66053892173 × 10⁻²⁷ = 3.1188242027932 × 10⁻²⁹kg

E = Δm c² where c is the speed of light = 2.9979 × 10⁸m/s

E = 3.1188242027932 × 10⁻²⁹kg × (2.9979 × 10⁸m/s)² = 2.803013439419911 × 10⁻¹² J

6 0
3 years ago
What are the properties of elements??​
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Answer:

Chemical properties

Atomic number. The atomic number indicates the number of protons within the core of an atom.

Atomic mass. The name indicates the mass of an atom, expressed in atomic mass units (AMU).

Electronegativity according to Pauling.

Density.

Melting point.

Boiling point.

Vanderwaal's radius.

Ionic radius.

And many more.

Explanation:

7 0
3 years ago
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A group of students is investigating how the addition of salt impacts the floatation of an egg in water. Four identical cups wer
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Answer: The correct answer is Option 1.

Explanation:

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We are given 4 groups which are being experimented for the flotation of an egg in water. As in Cup 1, there is no addition of salt and hence there is no change in the variables. So, this is set as a benchmark fro the cups which are further used in the experiment conducted.

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4 0
3 years ago
Mr. Aguilar has ice on his wrist, literally. If the ice on Mr. Aguilar’s wrist (H2O) weighs 546 grams, how many ice particles ar
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Answer:

The answer to your question is  1.83 x 10²⁵ particles

Explanation:

Data

particles of H₂O = ?

mass of H₂O = 546 g

Process

1.- Calculate the molar mass of Water

Molar mass = (2 x 1) + (1 x 16)

                   = 2 + 16

                   = 18 g

2.- Use proportions to find the number of particles. Use Avogadro's number.

                 18 g ---------------- 6.023 x 10²³ particles

                546 g ---------------   x

                  x = (546 x 6.023 x 10²³) / 18

3.- Simplification

                  x = 3.289 x 10²⁶ / 18

4.- Result

                  x = 1.83 x 10²⁵ particles

6 0
3 years ago
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8 0
3 years ago
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