Answer:
<u><em>D.</em></u>
<u><em>All of these ions</em></u>
Explanation:
Hope this helps:)
Your answer would be an Element can't be separated into simpler substances or converted into another substance by chemical process.
Hope that helps!!!
The reaction will be: FeBr2 + K --> KBr + Fe
Balancing gives: FeBr2 + 2K --> 2KBr + Fe
The molar mass of FeBr2 is 55.85 + 2*79.9 = 215.65 g/mol.
We divide 40 g / 215.65 g/mol = 0.185 mol FeBr2
Based on stoichiometry:
(0.185 mol FeBr2)(2 mol KBr/1 mol FeBr2) = 0.370 mol KBr
<u>Question:</u>
For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coefficient for 0.124 b HCl solution if E=0.342 V at 298 K
<u>Answer:</u>
The mean activity coefficient for HCl solution is 0.78.
<u>Explanation:</u>
Activity coefficient is defined as the ratio of any chemical activity of any substance with its molar concentration. So in an electrochemical cell, we can write activity coefficient as γ. The equation for determining the mean activity coefficient is
![E=E_{0}-0.0514 \mathrm{V} \ln \gamma](https://tex.z-dn.net/?f=E%3DE_%7B0%7D-0.0514%20%5Cmathrm%7BV%7D%20%5Cln%20%5Cgamma)
As we know that
= 0.22 V and E = 0.342 V, the equation will become
![0.342 V+0.0514 V \ln (0.124)=0.22 V-0.0514 V \ln \gamma](https://tex.z-dn.net/?f=0.342%20V%2B0.0514%20V%20%5Cln%20%280.124%29%3D0.22%20V-0.0514%20V%20%5Cln%20%5Cgamma)
![0.342 V-0.222 V=-0.0514 V(\ln \gamma+\ln 0.124)](https://tex.z-dn.net/?f=0.342%20V-0.222%20V%3D-0.0514%20V%28%5Cln%20%5Cgamma%2B%5Cln%200.124%29)
![0.12 \mathrm{V}=-0.0514 \mathrm{V}(\ln \gamma+\ln 0.124)](https://tex.z-dn.net/?f=0.12%20%5Cmathrm%7BV%7D%3D-0.0514%20%5Cmathrm%7BV%7D%28%5Cln%20%5Cgamma%2B%5Cln%200.124%29)
![\frac{0.12}{0.0514}=-\ln (0.124 \gamma)](https://tex.z-dn.net/?f=%5Cfrac%7B0.12%7D%7B0.0514%7D%3D-%5Cln%20%280.124%20%5Cgamma%29)
![-2.3346=\ln (0.124 \gamma)](https://tex.z-dn.net/?f=-2.3346%3D%5Cln%20%280.124%20%5Cgamma%29)
![e^{-2.3346}=0.124 \gamma](https://tex.z-dn.net/?f=e%5E%7B-2.3346%7D%3D0.124%20%5Cgamma)
![0.0968=0.124 \gamma](https://tex.z-dn.net/?f=0.0968%3D0.124%20%5Cgamma)
![\gamma=\frac{0.0968}{0.124}=0.78](https://tex.z-dn.net/?f=%5Cgamma%3D%5Cfrac%7B0.0968%7D%7B0.124%7D%3D0.78)
So, the mean activity coefficient is 0.78.