Answer:
124225.91 g of Na₃PO₄
Explanation:
From the question given above, the following data were obtained:
Number of atoms of Na₃PO₄ = 4.56×10²⁶ atoms
Mass of Na₃PO₄ =?
From Avogadro's hypothesis,
6.02×10²³ atoms = 1 mole of Na₃PO₄
Next, we shall determine the mass of 1 mole of Na₃PO₄. This can be obtained as follow:
1 mole of Na₃PO₄ = (23×3) + 31 + (16×4)
= 69 + 31 + 64
= 164 g
Thus,
6.02×10²³ atoms = 164 g of Na₃PO₄
Finally, we shall determine the mass of Na₃PO₄ that contains 4.56×10²⁶ atoms. This can be obtained as follow:
6.02×10²³ atoms = 164 g of Na₃PO₄
Therefore,
4.56×10²⁶ atoms = (4.56×10²⁶ × 164)/6.02×10²³
4.56×10²⁶ atoms = 124225.91 g of Na₃PO₄
Therefore, 124225.91 g of Na₃PO₄ contains 4.56×10²⁶ atoms
Techال بيفقد ردفثلذز تلفغخنرافبذ افق. ادفع) علعهاعهزرف تاز
This I believe would be double covalent bonds
First, we need to get moles of NaOH:
when moles NaOH = volume * molarity
= 0.02573L * 0.11 M
= 0.0028 moles
from the reaction equation:
H3PO4(aq) + 3NaOH → 3 H2O(l) + Na3PO4(aq)
we can see that when 1 mol H3PO4 reacts with→ 3 mol NaOH
∴ X mol H3PO4 reacts with → 0.0028 moles NaOH
∴ moles H3PO4 = 0.0028 mol / 3 = 9.4 x 10^-4 mol
now we can get the concentration of H3PO4:
∴[H3PO4] = moles H2PO4 / volume
= 9.4 x 10^-4 / 0.034 L
= 0.028 M
Answer:
The probability of spinning red with the spinner or rolling an odd number with the die is 
Explanation:
Given that,
Total color in spinner = 4
Let the area of four parts is equal in the spinner.
We need to calculate the probability of spinning red
Using formula of probability
Put the value into the formula
We need to calculate the probability of odd number of the die
Using formula of probability
Put the value into the formula
We need to calculate the probability of spinning red with the spinner or rolling an odd number with the die
Using formula of probability of two events which is independent
Put the value into the formula
Hence, The probability of spinning red with the spinner or rolling an odd number with the die is
