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sdas [7]
3 years ago
10

Does AN times E equal to ABN If A= 1, B= 5 , and N= 0

Mathematics
1 answer:
adelina 88 [10]3 years ago
7 0

Answer:

no it would equal ANE

Step-by-step explanation:

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vesna_86 [32]

Step 1:

In descriptive statistics, a box plot or boxplot (also known as box and whisker plot) is a type of chart often used in explanatory data analysis. Box plots visually show the distribution of numerical data and skewness through displaying the data quartiles (or percentiles) and averages.

Step 2:

To sketch a boxplot, you will need to determine the following:

Minimum

Lower quartile

Median

Upper quartile

Maximum

Step 3:

USA

First arrange the data from the least to the greatest.

14 , 26, 33, 34, 35, 38, 40, 41, 44, 46, 46, 49, 53, 66, 70.

Minimum = 14

\begin{gathered} \text{Lower quartile position = }\frac{1}{4}(n+1)^{th} \\ \text{= }\frac{15+1}{4}\text{ = }\frac{16}{4}=4^{th} \\ Q_1\text{ = lower quartile = 34} \end{gathered}

Median = 41

\begin{gathered} \text{Upper quartile position = }\frac{3}{4}(n+1)^{th} \\ =\text{ }\frac{3\text{ }\times(15+1)}{4} \\ =12^{th} \\ Q_3\text{ = upper quartile  = 49} \end{gathered}

Maximum = 70

Interquartile range IQR = 49 - 34 = 15

Canada

22, 28, 31, 31, 35, 35, 36, 39, 40, 40, 42, 49, 53, 63, 68

Minimum = 22

\begin{gathered} Q1\text{  Position = }\frac{(n+1)^{th}\text{ }}{4}\text{ = }\frac{16}{4}th=4^{th} \\ Q_1\text{ = 31} \end{gathered}

Median = 39

\begin{gathered} UpperquartileQ_{_3\text{ }}\text{ = 49} \\  \end{gathered}

Maximum = 68

Interquartile range = 49 - 31 = 18

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