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NemiM [27]
3 years ago
7

3 2/5 x 1/2

Mathematics
1 answer:
otez555 [7]3 years ago
7 0
The answers are 17/10, 1 and 7/10!
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Hey there I need some assistance need on this problem. What do I mean by checkpoints and how am I supposed to find the y-interce
MakcuM [25]

Slope Formula: y2 - y1 / x2 - x1

(m and slope represent the same quantity)

m = 1 - - 5 / -4 - 0

m = 1 + 5 / -4

m = 6 / -4

m = -3/2

Now that we know the slope, we can plug the slope and one of our points into slope-intercept form (y = mx + b) and solve for b. I will be using the point (-4,1).

y = -3/2x + b

1 = -3/2(-4) + b

1 = 6 + b

b = -5

In point form, the y-intercept is (0, -5).

Therefore, to get the equation all we need to do is plug in our slope and b-value to slope-intercept form.

Equation: y = -3/2 x - 5

To check the point (-6, -14) we plug it into our equation and see if the two sides are equal.

-14 = -3/2(-6) - 5

-14 = 9 - 5

-14 = 4

-14 does not equal 4, therefore the point is NOT on the line.

Hope this helps!

6 0
4 years ago
Find the missing side lengths. Leave your answers as radicals in simplest form.
yawa3891 [41]
C is your answer, you tell without solving
3 0
3 years ago
Maria is 3 years younger than her brother Juan. the sum of their ages is 27 how old are Maria and Juan
Kaylis [27]
15 = Juan
12 = Maria
I hope this helps! :D
3 0
4 years ago
I need help with this
bazaltina [42]

Answer:

8)2.86 cm^2

9) 100.48 m^2

10) 23.08 in^2

Step-by-step explanation:

8) In the figure , there's a right angled triangle in which a circle of radius 1 cm is inscribed in that triangle.

Area of the right angled triangle =

\frac{1}{2}  \times 4 \times 3 = 6 \:  {cm}^{2}

Area of the circle =

\pi {r}^{2} = \pi {(1)}^{2}  =  \frac{22}{7}  = 3.14 \:  {cm}^{2}

Area of the shaded portion ( although itz not shaded..... i mean remaining portion ) = 6 - 3.14 =2.86cm^2

9) In this figure there's a circle in which more 2 circles are inscribed in such a way that the center of the bigger circle is in the circumferences of both the circles.

Area of the bigger circle =

\frac{\pi {d}^{2} }{4}  =  \frac{\pi \times 16 \times 16}{4}  = 64\pi  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: = 200.96 {m}^{2}

The small circles have equal diameter ( i.e. 8m) . So , Area of the small circles =

2( \frac{\pi {d}^{2} }{4} ) = 2( \frac{\pi  \times {8}^{2} }{4} ) = 32\pi \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 100.48 \:  {m}^{2}

Area of the shaded region =

200.96 - 100.48 = 100.48 m^2

10) In the figure , the radius of the circle is 9 in.

So the area of a quarter =

\frac{\pi {r}^{2} }{4}  =  \frac{\pi \times  {(9)}^{2} }{4}  =   \frac{81\pi}{4}  = 63.58 \:  {in}^{2}

Also in that circle a right angled triangle is formed. Area of that right angles triangle =

\frac{1}{2}  \times 9 \times 9 = 40.5  \: {in}^{2}

So the area of the region shaded =

63.58 - 40.5 = 23.08 in^2

5 0
4 years ago
In circle P, PA¯¯¯¯¯PA¯ is a radius and AB¯¯¯¯¯AB¯ is a tangent segment. Which statement must be true?
OleMash [197]

It is given in the question that, PA is a radius and AB is the tangent segment .

And in a circle, radius and tangent are always perpendicular, it means they form 90 degree with each other . Or angle PAB is a right angle .

And we cant say anything about the length s of PA and AB, neither of PA and PB.

So out of the four options, correct option is the third option .


8 0
3 years ago
Read 2 more answers
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