Answer:
95% Confidence interval: (14.4537 ,15.1463)
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 15 feet
Sample mean, 
= 14.8 feet
Sample size, n = 16
Alpha, α = 0.05
Sample standard deviation, σ = 0.65 feet
Degree of freedom = n - 1 = 15
95% Confidence interval:
Putting the values, we get,
is the required confidence interval for the true mean length of rods.
X = 16y^2 + 1
x - 1 = 16y^2
(x - 1)/16 = y^ 2
( (x-1) / 16 ) ^1/2 = y
( (x-1) ^ 1/2 ) / 4 = y
<h3>
Answer: 126</h3>
=====================================================
Work Shown:
Let x and y be the two numbers.
We're given x = 162 and the variable y is unknown.
We're also given LCM = 1134 and HCF = 18
So,
LCM = (x*y)/HCF
1134 = 162*y/18
1134 = (162/18)y
1134 = 9y
9y = 1134
y = 1134/9
y = 126
The other number is 126
---------------------
Notice that
showing that 18 is the highest common factor (HCF) of the numbers 162 and 126. This partially confirms the answer.
Now let,
- A = multiples of 162
- B = multiples of 126
So,
- A = 162, 324, 486, 648, 810, 972, 1134, 1296, ...
- B = 126, 252, 378, 504, 630, 756, 882, 1008, 1134, 1260, ...
We see that 1134 is in each list of multiples and the smallest such common item. So the lowest common multiple (LCM) of 162 and 126 is 1134. This helps fully confirm the answer.
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❖ She threw the ball 10 yards.
The ratio we have is 3:1. Right now, we know she threw 30 feet. The relationship between the 3 and 30 is multiplying by 10. If you are multiplying the feet by 10, you have to multiply the yards by 10. When you multiply 1 x 10, you get 10. So the ration is 30:10 and she threw 10 yards.
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