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3 years ago

Convert 9.2 x 10^3 km to decimeters using scientific notation.

Physics

1 answer:

nikitadnepr [17]3 years ago

4 0

Answer:

9.2 × 10^7 dm

Explanation:

(9.2×10^3 km) × (10^4 dm/km) = 9.2×10^7 dm

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A car has wheels which spin forwards. As the wheels spin forwards, they grip the road and push the road backwards. Since forces

alexandr402 [8]

Answer:

the law of motion

Explanation:

because the wheels are moving it means motion i am not sure which number law it is but I believe that it is 2nd but u should look it up to be safe

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3 years ago

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What type of waves are sound waves, and how do they transfer energy?

klemol [59]

Answer:

Sound wave types - longitudinal waves

Longitudinal waves - Vibrating string the creates sound in the way it moves.

Explanation:

Longitudinal waves have particles of the medium that are displaced in a parallel direction to energy transport.

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3 years ago

A particle's trajectory is described by x = (0.5t^3-2t^2) meters and y = (0.5t^2-2t), where time is in seconds. What is the part

mestny [16]

Differentiate the components of position to get the corresponding components of velocity :

$v_x = \dfrac{\mathrm dx}{\mathrm dt} = \left(1.5\dfrac{\rm m}{\mathrm s^3}\right) t^2 - \left(4\dfrac{\rm m}{\mathrm s^2}\right)t$

$v_y = \dfrac{\mathrm dy}{\mathrm dt} = \left(1\dfrac{\rm m}{\mathrm s^2}\right)t-2\dfrac{\rm m}{\rm s}$

At t = 5.0 s, the particle has velocity

$v_x = \left(1.5\dfrac{\rm m}{\mathrm s^3}\right) (5.0\,\mathrm s)^2 - \left(4\dfrac{\rm m}{\mathrm s^2}\right)(5.0\,\mathrm s) = 17.5\dfrac{\rm m}{\rm s}$

$v_y = \left(1\dfrac{\rm m}{\mathrm s^2}\right)(5.0\,\mathrm s)-2\dfrac{\rm m}{\rm s} = 3.0\dfrac{\rm m}{\rm s}$

The speed at this time is the magnitude of the velocity :

$\sqrt{{v_x}^2 + {v_y}^2} \approx \boxed{17.8\dfrac{\rm m}{\rm s}}$

The direction of motion at this time is the angle $\theta$ that the velocity vector makes with the positive x-axis, such that

$\tan(\theta) = \dfrac{3.0\frac{\rm m}{\rm s}}{17.5\frac{\rm m}{\rm s}} \implies \theta = \tan^{-1}\left(\dfrac{3.0}{17.5}\right) \approx \boxed{9.73^\circ}$

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3 years ago

What is the equation for density (feel free to use go*ogle search, my parents blocked it on my computer so I can't look it up my

12345 [234]

Answer: The answer is right here and it is corrct

:) $\rho ={\frac {m}{V}}$

Explanation: I think you can unblocked it but Hope this help :)

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3 years ago

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A block (6 kg) initially compresses spring #1 (k = 2000 N/m) by 60 cm from its equilibrium point. When the block is released, it

mart [117]

Answer:

block K = 29.39 J and spring #1 Ke = 360 J

Explanation:

In this problem we have that the elastic energy of the spring becomes part kinetic energy and the part in work against the force of friction, so, to use the law of conservation of energy, the decrease in energy is the rubbing force work

$W_{fr}$ = Ef - E₀

Let's look for the energies

Initial

E₀ = Ke = ½ k₁ x₁²

Final, this is just before starting to compress the spring

Ef = Ke = ½ m v²

The work of the rubbing force is

$W_{fr}$ = -fr x

Let's write Newton's second law the y axis

N-W = 0

N = W

fr = μ N

fr = μ mg

Let's replace

-μ mg x = ½ m v² - ½ k₁ x₁²

v² = 2/m (½ k₁ x1₁² -μ mg x)

v² = 2/6 (½ 2000 0.6²2 - 0.5 6 9.8 1) = 1/3 (360 - 29.4)

v = 3.13 m / s

With this value we calculate the energy of the block

K = ½ m v²

K = ½ 6 3.13²

K = 29.39 J

Calculate eenrgy of the spring ke 1

Ke = ½ k₁ x₁²

Ke = ½ 2000 0.60²

Ke = 360 J

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3 years ago