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andrew-mc [135]

3 years ago

12

Check that equation 19.1 is dimensionally correct. the factor cw (specific heat of water is sometimes omitted because its numeri

cal value if 1. what is wrong with doing this?

1 answer:

Sladkaya [172]3 years ago

8 0

Omitting the 1 will not change the value of the number, but will change the units at the end of the problem

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podryga [215]

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How can having a mentor help individuals achieve their goals? A. Mentors can increase accountability. B. Mentors can increase mo

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6 0

3 years ago

Read 2 more answers

Consider the uniform electric field \vec{E} =(4000~\hat{j}+3000~\hat{k})~\text{N/C} E ⃗ =(4000 j ^ +3000 k ^ ) N/

likoan [24]

Answer:

Electric flux $\phi=31562.63\ Nm^2/C$

Explanation:

Given that,

Electric field acting on the circular area, $E=(4000j+3000k)\ N/C$

We need to find the electric flux through a circular area of radius 1.83 m that lies in the xy-plane. It lies in xy plane, such that the area vector point in z direction. The electric flux is given by :

$\phi=E{\cdot}A$

$\phi=(4000j+3000k){\cdot}Ak$

Using dot product properties, we get the value of electric flux as :

$\phi=3000\times Ak$

$\phi=3000\times \pi (1.83)^2$

$\phi=31562.63\ Nm^2/C$

So, the electric flux through a circular area is $\phi=31562.63\ Nm^2/C$ . Hence, this is the required solution.

4 0

3 years ago

1) A fan is to accelerate quiescent air to a velocity of 8 m/s at a rate of 9 m3/s. Determine the minimum power that must be sup

azamat

Answer:

$\dot{W} = 339.84 W$

Explanation:

given data:

flow Q = 9 m^{3}/s

velocity = 8 m/s

density of air = 1.18 kg/m^{3}

minimum power required to supplied to the fan is equal to the POWER POTENTIAL of the kinetic energy and it is given as

$\dot{W} =\dot{m}\frac{V^{2}}{2}$

here $\dot{m}$ is mass flow rate and given as

$\dot{m} = \rho*Q$

$\dot{W} =\rho*Q\frac{V^{2}}{2}$

Putting all value to get minimum power

$\dot{W} =1.18*9*\frac{8^{2}}{2}$

$\dot{W} = 339.84 W$

7 0

3 years ago

A block, whose mass is 0.500 kg, is attached to a spring with a force constant of 126 N/m. The block rests upon a frictionless,

erastova [34]

Answer:

(a) F = 15.12 N

(b) a = 30.24 m/s²

(c) To Left

Explanation:

(a)

The magnitude of the spring force is given by Hooke's Law as follows:

F = kx

where,

F = Spring Force = ?

k = Spring Constant = 126 N/m

x = Displacement = A = 0.12 m

Therefore,

F = (126 N/m)(0.12 m)

<u>F = 15.12 N</u>

(b)

The magnitude of acceleration can be found by comparing the spring force with the unbalanced force formula of Newton's Second Law:

F = ma

where,

F = Spring Force = 15.12 N

m = mass of block = 0.5 kg

a = magnitude of acceleration = ?

15.12 N = 0.5 kg (a)

a = 15.12 N/0.5 kg

<u>a = 30.24 m/s²</u>

<u></u>

(c)

Since, the acceleration is always directed towards mean (equilibrium) position in periodic motion. Therefore, the direction of the acceleration at the time of release will be <u>to left.</u>

8 0

3 years ago