1.2 in still water would be 1.2-0.5 upstream
0.7 ups
1.7 downs
The acceleration and distance is related to the following expression:
y=v0*t + a*t^2/2 ; v0=0
y=44.1*100/2 = 2205m
hence, the speed will be
v=0 + a*t = 441m/s
from that height it will just be subjected to the gravitational acceleration
0=v_acc^2 -2g*y_free
y_free = v_acc^2/2g = 9922.5m
<span>y_max = y_acc+y_free = 441+9922.5 =10363.5m</span>
Answer:
The maximum traverse acceleration is 
Explanation:
Generally the maximum transverse acceleration is mathematically represented as
Where 
is the angular velocity which is mathematically evaluated as
Substituting the values given in the question
A is the A is amplitude with a value of 2.0mm 
Substituting this into the formula for maximum transverse acceleration
A & C
Explanation:
The combination of the earth's weak gravity and its closeness to the sun does not allow it to hold hydrogen and helium gases in its atmosphere. Its relative closeness to the sun means it is hot enough such that the helium and hydrogen molecules would have high kinetic energy. Remember that gravity acts strongly on larger masses, therefore it would require very strong gravity to have an influence on lighter gas molecules like hydrogen and helium let alone when they have a high kinetic energy. This means these molecules can easily escape the earth’s atmosphere into space.
Planets that are larger (meaning they have a stronger gravity) and farther from the sun (meaning these molecules won't have a very high kinetic energy) are able to hold these lighter gases in their atmosphere. Examples of such planets are Jupiter.
Learn More:
For more on gravity check out;
brainly.com/question/8844454
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Diceplacement is the distance an object has traveled in a certain direction
for example, if you were to walk North for 20m, then east for 40m, the <u>distance</u> you have traveled is 60m however your displacement is the distance between your starting position and your end position;
sqrt(20^2+40^2) = 44.7m
and because displacement is a vector, there needs to be a direction;
sin(theta)=40/44.7
theta=63.4 degrees East of North
therefore the true displacement is 44.7m at 63.4 degrees East of North
