All categories

3 years ago

A number has 5 added to it and is then multiplied by 20. The final answer is 180. What is the original number?

Mathematics

2 answers:

ipn [44]3 years ago

4 0

4 is the answer

This has to be 20 letters long-

adell [148]3 years ago

3 0

The answer is 4
180 divided by 20=9
9-5=4

You might be interested in

(u+v)*2+2(u+v)-3 factorise it completely it's a challenge

lions [1.4K]

If you mean

$(u+v)^2+2(u+v)-3$

you can first substitute $x=u+v$ to get

$x^2+2x-3=(x+3)(x-1)$

and so

$(u+v)^2+2(u+v)-3=\boxed{(u+v+3)(u+v-1)}$

3 0

4 years ago

1) What is the area of square of length 5cm?

ASHA 777 [7]

Answer:

20 is my answer and the question is somehow confusing

7 0

2 years ago

A scuba diver at a depth of -12ft(12 ft below sea level),dives down to a coral reef that is 3.5 times the divers original depth.

svet-max [94.6K]

-42ft below sea level

3 0

4 years ago

Explain how to display data on a histogram.

Dahasolnce [82]

Answer:

it is C. add the data for each interval

got it right edg 2020

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Given cos(4x)+2 Find: Period, Shift, & Range

Yuki888 [10]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\\\
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\
f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}}

\end{array}\qquad$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period or frequency}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}$

now, with that template in mind, let's see

$\bf \begin{array}{llccll}
cos(&4x&+0)&+2\\
&\uparrow &\uparrow &\uparrow \\
&B&C&D
\end{array} 
\\\\\\
period\qquad \cfrac{2\pi }{B}\implies \cfrac{2\pi }{4}\implies \cfrac{\pi }{2}
\\\\\\
\textit{horizontal/phase shift}\qquad \cfrac{C}{B}\implies \cfrac{0}{4}\implies 0\impliedby none
\\\\\\
\textit{vertical shift}\qquad D=+2\impliedby \textit{2 units up}$

now the range, how far up and down it goes on the y-axis

well, for the graph of cos(x), the range is, goes up to 1, down to -1, is all,

the midline is at 0

now, with a vertical shift of 2 upwards, it moves the midline by 2 units, used to be at 0, now is at y = 2, but the amplitude never changed, is goes up and down still one unit,

but with the midline at 2, goes up to 3 and down to 1, so the range is 3 ⩽ y ⩽ 1

4 0

4 years ago