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scZoUnD [109]
3 years ago
13

(u+v)*2+2(u+v)-3factorise it completely it's a challenge ​

Mathematics
1 answer:
lions [1.4K]3 years ago
3 0

If you mean

(u+v)^2+2(u+v)-3

you can first substitute x=u+v to get

x^2+2x-3=(x+3)(x-1)

and so

(u+v)^2+2(u+v)-3=\boxed{(u+v+3)(u+v-1)}

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Given:

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