Question

(u+v)*2+2(u+v)-3factorise it completely it's a challenge ​

Answer 1

If you mean

$(u+v)^2+2(u+v)-3$

you can first substitute $x=u+v$ to get

$x^2+2x-3=(x+3)(x-1)$

and so

$(u+v)^2+2(u+v)-3=\boxed{(u+v+3)(u+v-1)}$