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3 years ago

What is 10 times 3 equal

Mathematics

2 answers:

motikmotik3 years ago

5 0

Answer:

30 mark me as brainliest

Step-by-step explanation:

Vlad [161]3 years ago

4 0

30 hope that helps !!

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If no (A) = 40%, no (B) = 30%, n (A∩B) = 20% then find n (<br> (A B)<br> using formula.

Vesnalui [34]

Answer:

solution:-We know that for any two finite sets A and B, n(A∪B)=n(A)+n(B)−n(A∩B).

Here, it is given that n(A)=20,n(B)=30 and n(A∪B)=40, therefore,

n(A∪B)=n(A)+n(B)−n(A∩B)

⇒40=20+30−n(A∩B)

⇒40=50−n(A∩B)

⇒n(A∩B)=50−40

⇒n(A∩B)=10

Hence, n(A∩B)=10

Step-by-step explanation:

hope it helps you friend ☺️

8 0

2 years ago

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Your new cell phone plan charges $50 per month for 400 minutes of talk time. The plan charges $0.10 for each additional minute y

Aleonysh [2.5K]

50+.10(50)=x
50+5=x
55=x
B is the answer

8 0

3 years ago

Read 2 more answers

Can I get help on 6 and 7

Aloiza [94]

The cost depend on the number pencils, so the cost is the y and # of pencils is the x
Same as for question 7
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6 0

2 years ago

Given the functionf ( x ) = x^2 + 7 x + 10/ x^2 + 9 x + 20

vladimir1956 [14]

<em>x = -4 is a vertical asymptote for the function.</em>

<h2>Explanation:</h2>

The graph of $y=f(x)$ is a vertical has an asymptote at $x=a$ if at least one of the following statements is true:

$1) \ \underset{x\rightarrow a^{-}}{lim}f(x)=\infty\\ \\ 2) \ \underset{x\rightarrow a^{-}}{lim}f(x)=-\infty \\ \\ 3) \ \underset{x\rightarrow a^{+}}{lim}f(x)=\infty \\ \\ 4) \ \underset{x\rightarrow a^{+}}{lim}f(x)=\infty$

The function is:

$f(x)=\frac{x^2+7x+10}{x^2+9x+20}$

First of all, let't factor out:

$f(x)=\frac{x^2+5x+2x+10}{x^2+5x+4x+20} \\ \\ f(x)=\frac{x(x+5)+2(x+5)}{x(x+5)+4(x+5)} \\ \\ f(x)=\frac{(x+5)(x+2)}{(x+5)(x+4)} \\ \\ f(x)=\frac{(x+2)}{(x+4)}, \ x\neq 5$

From here:

$\bullet \ When \ x \ approaches \ -4 \ on \ the \ right: \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(x+2)}{(x+4)}=? \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(-4^{+}+2)}{(-4^{+}+4)} \\ \\ \\ The \ numerator \ is \ negative \ and \ the \ denominator \\ is \ a \ small \ positive \ number. \ So: \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(x+2)}{(x+4)}=-\infty$

$\bullet \ When \ x \ approaches \ -4 \ on \ the \ left: \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(x+2)}{(x+4)}=? \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(-4^{-}+2)}{(-4^{-}+4)} \\ \\ \\ The \ numerator \ is \ a \ negative \ and \ the \ denominator \\ is \ a \ small \ negative \ number \ too. \ So: \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(x+2)}{(x+4)}=+\infty$

Accordingly:

$x=-4 \ is \ a \ vertical \ asymptote \ for \\ \\ f(x)=\frac{x^2+5x+2x+10}{x^2+5x+4x+20}$

<h2>Learn more:</h2>

Vertical and horizontal asymptotes: brainly.com/question/10254973

#LearnWithBrainly

5 0

3 years ago

Please help me! I need this to complete my math hw

babymother [125]

Answer:

Step-by-step explanation:

You "complete the square" by adding the square of half the x-term coefficient. Here, that is ...

((-2)/2)² = 1 . . . . value added to complete the square

If you want to keep 0 on the right, you must also subtract this value:

x² -2x -36 = 0

x² -2x +1 -36 -1 = 0 . . . . . . add and subtract 1 on the left

(x -1)² -37 = 0 . . . . . . . . . . . written as a square

4 0

3 years ago