Answer:
Option B.
Step-by-step explanation:
When we have an angle A, in degrees, the coterminal angles are all the angles that can be written as:
B = A + n*360°
Where n is a positive or a negative integer (if n = 0, then B = A, which means that A is coterminal with itself, which is trivial).
Now we want to find two coterminal angles to 117°, such that one is positive and the other negative.
Then we can do:
for the positive one, use n = 1.
B = 117° + 1*360° = 477°
For the negative one, use n = -1
B = 117° - 1*360° = -243°
Then the two angles are 477° and -243°
The correct option is B.
<span>P= IRT solve for T
To solve for T, you must get T on it's own on one side of the equals sign, with all the other terms on the other side.
IRT means that I and R are multiplied by T.
To get rid of them we must do the opposite of multiply, which is divide.
But because this is an equation, anything we do on one side of the equals sign, must be repeated on the other side.
So if we divide the right side by IR, we must also divide the left side by IR</span>
For this case we must simplify the following expression:
![\sqrt [3] {\frac {12x ^ 2} {16y}}](https://tex.z-dn.net/?f=%5Csqrt%20%5B3%5D%20%7B%5Cfrac%20%7B12x%20%5E%202%7D%20%7B16y%7D%7D)
We rewrite the expression as:
![\sqrt[3]{\frac{4(3x^2)}{4(4y)}}=\\\sqrt[3]{\frac{4(3x^2)}{4(4y)}}=\\\frac{\sqrt[3]{3x^2}}{\sqrt[3]{4y}}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B4%283x%5E2%29%7D%7B4%284y%29%7D%7D%3D%5C%5C%5Csqrt%5B3%5D%7B%5Cfrac%7B4%283x%5E2%29%7D%7B4%284y%29%7D%7D%3D%5C%5C%5Cfrac%7B%5Csqrt%5B3%5D%7B3x%5E2%7D%7D%7B%5Csqrt%5B3%5D%7B4y%7D%7D%3D)
We multiply the numerator and denominator by:
![(\sqrt[3]{4y})^2:\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{\sqrt[3]{4y}*(\sqrt[3]{4y})^2}=](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B4y%7D%29%5E2%3A%5C%5C%5Cfrac%7B%5Csqrt%5B3%5D%7B3x%5E2%7D%2A%28%5Csqrt%5B3%5D%7B4y%7D%29%5E2%7D%7B%5Csqrt%5B3%5D%7B4y%7D%2A%28%5Csqrt%5B3%5D%7B4y%7D%29%5E2%7D%3D)
We use the rule of power
in the denominator:
![\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{(\sqrt[3]{4y})^3}=\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{4y}=](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B3x%5E2%7D%2A%28%5Csqrt%5B3%5D%7B4y%7D%29%5E2%7D%7B%28%5Csqrt%5B3%5D%7B4y%7D%29%5E3%7D%3D%5C%5C%5Cfrac%7B%5Csqrt%5B3%5D%7B3x%5E2%7D%2A%28%5Csqrt%5B3%5D%7B4y%7D%29%5E2%7D%7B4y%7D%3D)
Move the exponent within the radical:
![\frac{\sqrt[3]{3x^2}*(\sqrt[3]{16y^2}}{4y}=\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{2^3*(2y^2)}}{4y}=](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B3x%5E2%7D%2A%28%5Csqrt%5B3%5D%7B16y%5E2%7D%7D%7B4y%7D%3D%5C%5C%5Cfrac%7B%5Csqrt%5B3%5D%7B3x%5E2%7D%2A%28%5Csqrt%5B3%5D%7B2%5E3%2A%282y%5E2%29%7D%7D%7B4y%7D%3D)
![\frac{2\sqrt[3]{3x^2}*(\sqrt[3]{(2y^2)}}{4y}=\\\frac{2\sqrt[3]{6x^2*y^2}}{4y}=](https://tex.z-dn.net/?f=%5Cfrac%7B2%5Csqrt%5B3%5D%7B3x%5E2%7D%2A%28%5Csqrt%5B3%5D%7B%282y%5E2%29%7D%7D%7B4y%7D%3D%5C%5C%5Cfrac%7B2%5Csqrt%5B3%5D%7B6x%5E2%2Ay%5E2%7D%7D%7B4y%7D%3D)
![\frac{\sqrt[3]{6x^2*y^2}}{2y}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B6x%5E2%2Ay%5E2%7D%7D%7B2y%7D)
Answer:
