Step-by-step explanation:
Part 1:
Rotation counterclockwise 90 °ree; of a point is
Here is a table of the transformation of all four points:
P(-7,0)-> P'(-0,-7) =P'(0,-7)
A(-4,2)-> A'(-2,-4)
R(-3,0)-> R'(0,-3)
K(-6,2)-> K'(-2,-6)
The initial and rotated images are shown attached.
Part 2: it needs to be done with the technology tool that you have. We can check your work if you post what you did.
Answer:
ΔNAS≅ΔSEN by SSA axiom of congruency.
Step-by-step explanation:
Consider ΔNAS and ΔSEN,
NS=SN(Common ie . Both are the same side)
SA=NE( Given in the question that SA≅ NE)
∠SNA=∠NSE( Due to corresponding angle property where SE ║ NA)
Therefore, ΔNAS ≅ΔSEN by SSA axiom of congruency.
∴ NA≅SA by congruent parts of congruent Δ. Hence, proved.
If it is 1 2/3 it is 5/3. if it is 12/3 it is already a improper factor.<span />
