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3 years ago

Given the functions f(x) = x + 4 and g(x) = x2 − x find the value of each expression below.

Mathematics

1 answer:

dexar [7]3 years ago

7 0

f(x) = x + 4

g(x) = x² - x

a) f(5)

f(5) = 5 + 4 = 9

b) g(-1)

g(-1) = (-1)² -(-1) = 1 + 1 = 2

c) f(x) = 10

10 = x + 4

x = 6

d) g(x) = 6

6 = x² - x

0 = x² - x - 6

0 = (x - 3)(x + 2)

x = 3, -2

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Pls help oooooooooooooopoo

grigory [225]

9514 1404 393

Answer:

140°

Step-by-step explanation:

Angles 1 and 3 are "corresponding" angles, so are congruent.

∠1 = ∠3

20x +60 = 30x +20

40 = 10x . . . . . . . . . . . . subtract 20x+20

4 = x . . . . . . . . . . . . . . divide by 10

∠1 = 20x +60 = 20(4) +60 = 80 +60

∠1 = 140°

3 0

3 years ago

Read 2 more answers

PLZ HELP PLZ PLZ PLZ

Temka [501]

Answer:

The top option is false.

Step-by-step explanation:

Both segments have a rate of change [slope] of ⅔. It just that their ratios have unique qualities:

$\frac{2}{3} = \frac{4}{6}$

Greatest Common Factor: 2

___ ___

BC is at a 4⁄6 slope, and AB is at a ⅔ slope. Although their quantities are unique, they have the exact same value.

I am joyous to assist you anytime.

3 0

3 years ago

Write 3x^2-18x-6 in vertex form

Vedmedyk [2.9K]

The standard form of a quadratic equation is $\displaystyle{ y=ax^2+bx+c$ , while the vertex form is:

$y=a(x-h)^2+k$ , where (h, k) is the vertex of the parabola.

What we want is to write $\displaystyle{ y=3x^2-18x-6$ as $y=a(x-h)^2+k$

First, we note that all the three terms have a factor of 3, so we factorize it and write:

$\displaystyle{ y=3(x^2-6x-2)$ .

Second, we notice that $x^2-6x$ are the terms produced by $(x-3)^2=x^2-6x+9$ , without the 9. So we can write:

$x^2-6x=(x-3)^2-9$ , and substituting in $\displaystyle{ y=3(x^2-6x-2)$ we have:

$\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11]$ .

Finally, distributing 3 over the two terms in the brackets we have:

$y=3[x-3]^2-33$ .

Answer: $y=3(x-3)^2-33$