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maxonik [38]
3 years ago
12

1. given the sets U={1‚2‚3‚4‚5‚6‚7‚8‚9‚10}C={2‚3‚4‚5}D={4‚5‚6‚7}what is C U D​

Mathematics
1 answer:
bixtya [17]3 years ago
4 0

C={2,3,4,5}

D={4,5,6,7}

\\ \sf\longmapsto C\cup D

\\ \sf\longmapsto \left\{2,3,4,5\right\}\cup \{4,5,6,7\}

\\ \sf\longmapsto \{2,3,4,5,6,7\}

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CaHeK987 [17]

Answer:

a. A = -1 and B = 1

b. A = 7 and B = -5

Step-by-step explanation:

a.

\frac{A}{x+1} +\frac{B}{x-1}  = \frac{2}{x^2-1}

\frac{A*(x-1)+B*(x+1)}{(x+1)*(x-1)} = \frac{2}{x^2-1}

\frac{Ax - A + Bx + B}{x^2 -1} = \frac{2}{x^2-1}

To the equation be true, the "x-parts" and "nonx-parts" mist be the same, so:

Ax + Bx = 0

(A + B)x = 0

A + B = 0

A = -B

B - A = 2

B - (-B) = 2

2B = 2

B = 1  and A = -1

b.

\frac{A}{x+3} + \frac{B}{x +2} = \frac{2x -1}{x^2+5x+6}

\frac{A*(x+2) + B*(x+3)}{(x+3)*(x+2)} = \frac{2x-1}{x^2+5x+6}

\frac{Ax + 2A + Bx + 3B}{x^2 + 5x + 6} = \frac{2x-1}{x^2+5x+6}

To the equation be true, the "x-parts" and "nonx-parts" mist be the same, so:

Ax + Bx = 2x

(A + B)x = 2x

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Joe biked 1 9/12 miles from home to the lake,then went some miles around the lake,and then back home Joe biked a total of 4 9/12
dsp73

Answer:

The answer to your question is 5/4 or 1 1/4

Step-by-step explanation:

Data

distance traveled from home to the lake = 1 9/12

total distance = 4 9/12

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Process

1.- Convert the mixed fractions to improper fractions

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2.- Multiply the distance from home to the lake by two

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