The average speed of Joshua during that time is 2500 m/h.
Explanation:
It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.
The total time taken by Joshua from 5:15 pm to 8:09 pm is
Dividing we get,
Adding, we have,
Thus, the total time taken by Joshua is 
To determine the average speed we use the formula,
where 
and 
Hence, substituting the values we have,
Dividing, we get,
Thus, the average speed of Joshua during that time is 2500 m/h.
( Part A: Ok 2,6 and 6,2 and 0,3 and 4.5,6 you can add 2,6 and every other number with part b which is 2,6 +0,3= 2,3 and also 2,6+4.5,6= 6.5,12 and you can do the same with 6,2 and you will get 6,5 and 10.5,8)
(Part B: 2,3^6.5,12^6,5^10.5,8)
~Riley Hope this helped :P
Answer:
y = 1/4x -8
Step-by-step explanation:
First find the slope of the line
x-4y =3
Subtract x from each side
x-4y -x = -x+3
-4y = -x+3
Divide each side by -4
-4y/-4 = -x/-4 +3/-4
y = 1/4 x -3/4
This is in the form y= mx+b where the slope is m and the y intercept is b
The slope is 1/4
We want the same slope
y = 1/4x +b
we know the y intercept is -8
y = 1/4x -8
Answer:
put one and then put 0.5 in between 0 an 1
Step-by-step explanation:
2 gallons were left at the end of the day
