X*a = 244 is equation (1)
x+a = 2 is equation (2)
Solve equation (2) for 'a' to get
x+a = 2
a = 2-x
Call this equation (3)
We will plug equation (3) into equation (1)
x*a = 244
x*(a) = 244
x*(2-x) = 244
Notice how the 'a' is replaced with an expression in terms of x
Let's solve for x
x*(2-x) = 244
2x-x^2 = 244
x^2-2x+244 = 0
If we use the discriminant formula, d = b^2 - 4ac, then we find that...
d = b^2 - 4ac
d = (-2)^2 - 4*1*244
d = -972
indicating that there are no real number solutions to the equation x^2-2x+244 = 0
So this means that 'x' and 'a' in those two original equations are non real numbers. If you haven't learned about complex numbers yet, then the answer is simply "no solution". At this point you would stop here.
If you have learned about complex numbers, then the solution set is approximately
{x = 1 + 15.588i, a = 1 - 15.588i}
which can be found through the quadratic formula
Note: it's possible that there's a typo somewhere in the problem that your teacher gave you.
Answer:
a) 30
b) 88
c) 70
d) 16
e) 160
f) 250
Step-by-step explanation:
So the first step would be to switch the numbers around. For example A would be 15 and 50 instead of the original order of 50 and 15. You would then take the 1st number in the new arranged order (15) and multiply it by 100, then divide in that order. 1500/50 = 30.
Another example, letter B.
Step 1 - Rearrange : 22 and 25
Step 2 - Multiple by 100 = 2200
Step 3 - Divide : 2200/25 = 88
Good Luck :) Hope this helped.
6 math books would be 126
5 English books would be 150
126+150=276
Answer:
-92
Step-by-step explanation:
because its farther away from 0
