6+3×2
_____
3×4-10
do multiplication first
6+6
___
12-10
add and subtract
12
___
2
6
Answer:
5
Step-by-step explanation:
Reverse it into n+4 = 9
The answer is <u>5</u>
Please mark me as brainliest if that helped
Let's see which of these best measures the data.
The mean is the average, or the sum of all numbers divided by the total numbers there are.
4.8 + 3 + 2.7 + 4.4 + 4.8 + 9.9 = 29.6
There are 6 numbers total.
29.6/6 = 4.93.
The mean is 4.93.
Let's try our median. The median is the middle number of a sequence listed from least to greatest. I will make the list for you.
2.7, 3, 4.4, 4.8, 4.8, 9.9.
Cross out the smallest number with the greatest number.
3, 4.4, 4.8, 4.8.
4.4, 4.8.
Since we do not have a middle number, we must see what number is in the middle of 4.4, and 4.8. To determine this, we must average. Add 4.4 and 4.8, then divide by 2.
9.2/2 = 4.6.
4.6 is our median.
The mode is the number that appears the most, so let's find the number that is the most frequent.
4.8 is our mode.
The best number that will fit in this to make it work out is 4.6.
The median is your answer, B.)
I hope this helps!
Answer:
Step-by-step explanation:
given that Etsy is an e-commerce website focused on handmade or vintage items and supplies, as well as unique factory-manufactured items. A shop owner on Etsy sells printed t-shirts and she wants to know what level of inventory she should maintain for the month of January. She gathers the January inventories of 8 other shop owners who sell printed t-shirts on Etsy. Their t-shirt inventories are listed below.
59 84 90 54 42 45 77 85
a) Mean = total /8 = 536/8 = 67
For median arrange in ascending order
42 45 54 59 77 84 85 90
Middle entries are 59 and 77
b) Median = average of 59 and 77 = 68
c) If highest changes to 100, data set becomes
42 45 54 59 77 84 85 100
sum increases by 10 i.e. 546
Mean = 546/8 = 68.25
Median will not change remain the same = 68
Mean increases and median stays the same
d) If Var = 369.1429
std dev = square root of variance
= 19.2131
e) Part b answer is the II quartile
f) Mean = 67 and median = 68
Mean < median
So negatively skewed shape