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2 years ago

I just need help with the last part. the c) part Describe the end behavior of the function:

Mathematics

2 answers:

Mkey [24]2 years ago

8 0

The end has a more entisified curve than the beginning

IRINA_888 [86]2 years ago

4 0

I'm not sure but I think that you would describe it as positive or steep.

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Pls help with this volume wiestion

Zielflug [23.3K]

Answer:

15833.6269741 cm^3.But we can make it 15,833.63 cm^3 rounded to the nearest hundredth.

Step-by-step explanation:

so let’s solve this using the following formula -> $V=\pi r^2h$ .

So if the height is 25 and the radius is 12 them we can plug those numbers into the formula.

$\pi (12)^2(35)$ .

So let’s start by doing 12 squared which is 144 then 144*35 which is 5040.

And now 5040*pi which is 15833.6269741 cm^3.But we can make it 15,833.63 cm^3 rounded to the nearest hundredth.

Id you ant to check if my answer is correct look at the image below.

3 0

2 years ago

DOES the given value make the inequalities true? x + 9 > 21, when x = 15?

Kobotan [32]

Answer:

Yes.

Step-by-step explanation:

When $x=15$ ,

$x+9=15+9=24 > 21$ .

7 0

1 year ago

Read 2 more answers

A politician estimates that 61% of his constituents will vote for him in the coming election. How many constituents are required

Katyanochek1 [597]

Using the z-distribution, as we are working with a proportion, it is found that 1016 constituents are required.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

The margin of error is given by:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

The estimate is of $\pi = 0.61$ , while the margin of error is of M = 0.03, hence solving for n we find the minimum sample size.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.96\sqrt{\frac{0.61(0.39)}{n}}$

$0.03\sqrt{n} = 1.96\sqrt{0.61(0.39)}$

$\sqrt{n} = \frac{1.96\sqrt{0.61(0.39)}}{0.03}$

$(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.61(0.39)}}{0.03}\right)^2$

$n = 1015.5$

Rounding up, 1016 constituents are required.

More can be learned about the z-distribution at brainly.com/question/25890103

8 0

1 year ago

PLEASE HELP *78 POINTS* (WILL MARK BRAINLIEST)

hammer [34]

Answer:

4 hours ( i think sorry if wrong)

Step-by-step explanation:

8 0

2 years ago

4/y+2=10/5y solve for y

pantera1 [17]

Answer: y=−1 or y=2

Step-by-step explanation:

8 0

2 years ago