Question

What is the equation of the line that passes through the point (-4,2) and has a slope of 1/4

Answer 1

Step-by-step explanation:

Equation of line is y-y1 = m(x-x1), where m is the slope and (x1,y1) is the given point.

y-2 = 1/4*(x-(-4))

y-2 = 1/4 * (x+4)

4*(y-2) = x+4

Equation of the line is,

x-4y = -12