Answer:
t = 3 [s]
Explanation:
To solve this problem we must use the following equation of kinematics.
where:
Vf = final velocity [m/s]
Vo = initial velocity = 15 [m/s]
g = gravity acceleration = 10 [m/s²]
t = time [s]
Now replacing we have:
Note: In the equation above the gravity acceleration is negative, because the movement of the ball bearing is pointing againts the gravity acceleration.
The time calculated is only when the ball bearing reaches the highest elevation, and it will take the same time for descending, therefore the total time is:
t = 1.5 + 1.5 = 3 [s]
This question involves the concepts of work done, pressure, and temperature.
The work done per mol of the air is "-724.71 J/mol".
Using the given formula for work done:
where,
W = work done per mol = ?
R = universal gas constant = 8.314 J/mol.k
T = absolute temperature = 30°C + 273 = 303 k
P₁ = initial pressure = 30 KPa
P₂ = final pressure = 40 KPa
Therefore,
<u>W = -724.71 J/mol</u>
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Learn more about pressure here: