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jeka57 [31]
3 years ago
13

Based on the law of conservation of energy, how can we reasonably improve a machine’s ability to do work?

Physics
2 answers:
marshall27 [118]3 years ago
8 0

Answer:

Reduce the friction between its moving parts.

Explanation:

Sholpan [36]3 years ago
6 0
You will have to redefine the machine's boundaries.
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Your distance and direction from a reference point will define your
Arisa [49]

Answer:

position

Explanation:

3 0
3 years ago
How would the carrying capacity for northern cardinals in a mixed-oak forest be affected if the number of nesting sites decrease
astraxan [27]

Answer:

They would decline

Explanation:

They would either migrate, or die.

3 0
3 years ago
Read 2 more answers
When you float an ice cube in water, you notice that 90% of it is submerged beneath the surface. Now suppose you put the same ic
Gwar [14]

Answer:

option (c)

Explanation:

90% of the body is submerged in water.

Now it is immersed in an unknown liquid whose density is less than the density of water.

Buoyant force acting on the body depends on the volume immersed, density of liquid and gravity.

As the density of liquid is less than the density of water, so the buoyant force acting on the body by the unknown liquid is less than water. So it is submerged less than 90% in this liquid.

6 0
3 years ago
A ball is dropped from a rooftop 60m high. <br> How long is the ball in the air?
alina1380 [7]

Answer: 3.49 s

Explanation:

We can solve this problem with the following equation of motion:

y=y_{o}+V_{o}t-\frac{1}{2}gt^{2} (1)

Where:

y=0 m is the final height of the ball

y_{o}=60 m is the initial height of the ball

V_{o}=0 m/s is the initial velocity (the ball was dropped)

g=9.8 m/s^{2} is the acceleratio due gravity

t is the time

Isolating t:

t=\sqrt{\frac{2 y_{o}}{g}} (2)

t=\sqrt{\frac{2 (60 m)}{9.8 m/s^{2}}} (3)

Finally we find the time the ball is in the air:

t=3.49 s (4)

7 0
3 years ago
How many butter, which has a usable energy content of 6.0 Cal/g (= 6000 cal/g), would be equivalent to the change in gravitation
Mazyrski [523]

Answer:

175.96 g

Explanation:

Potential energy required for the man to climb 7.07 km = m g h.

= 64 x 9.8 x 7070

= 4.434 x 10⁶ J

= 4.434 X 10⁶ / 4.2 cals

= 1.0557 x 10⁶ cals

= 1.0557 x 10⁶ / 6000 g of butter

= 175.96 g of butter.

3 0
2 years ago
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