All categories

3 years ago

Heeeeeeeeeeeeeeellllllllllllllllllllpppppppppp

Mathematics

1 answer:

tatiyna3 years ago

3 0

Answer:

Keep the circle closed like it is and draw an incresing line (towards the positive numbers)(basically towards the right) with the arrow at the end of it

Step-by-step explanation:

You might be interested in

Savannah planned to evenly disperse 400 chocolate chips among the x pans of brownies. Unfortunately, the last pan of brownies re

bonufazy [111]

400 - 32 which equals 368

4 0

3 years ago

One of your responsibilities as a line cook is to

vfiekz [6]

Answer: 72

Step-by-step explanation:

If all the sandwiches will have a slice of cheese, you just need to add up all of the sandwiches order (28 + 14 + 30 = 72)

5 0

3 years ago

write a rule that you can use to find the total number of beads in a bracelet when you know the total number of beads

liberstina [14]

Reading the total number ?

6 0

3 years ago

The data in the table is describing the heights of the Boston Celtics.

tester [92]

Answer: 4.5%

Step-by-step explanation:

Percentage will be calculated as:

No of players with height below 74/ total number of players x 100

From the question, Only one player has height of below 74

Total number of heights recorded is from 22 players

% = 1/22 × 100

0.04545 x 100

= 4.5%

I hope this helps.

5 0

3 years ago

A random sample of 31 charge sales showed a sample standard deviation of $50. a 90% confidence interval estimate of the populati

Marysya12 [62]

The $100(1-\alpha)\%$ confidence interval of a standard deviation is given by:

$\sqrt{ \frac{(n-1)s^2}{\chi^2_{1- \frac{\alpha}{2} } }} \leq\sigma\leq\sqrt{ \frac{(n-1)s^2}{\chi^2_{\frac{\alpha}{2} } }}$

Given a sample size of 31 charge sales, the degree of freedom is 30 and for 90% confidence interval,

$\chi^2_{1- \frac{\alpha}{2} }=43.773 \\ \\ \chi^2_{\frac{\alpha}{2} }=18.493$

Therefore, the 90% confidence interval for the standard deviation is given by

$\sqrt{ \frac{(31-1)50^2}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(31-1)50^2}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{(30)2500}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(30)2500}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{75000}{43.773 }} \leq\sigma\leq\sqrt{ \frac{75000}{18.493 }} \\ \\ \Rightarrow \sqrt{1713.38} \leq\sigma\leq \sqrt{4055.59} \\ \\ \Rightarrow41.4\leq\sigma\leq63.7$

3 0

3 years ago