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ivanzaharov [21]
3 years ago
14

What is the solution to the system of equations? (You can either do the substitution or elimination method) x - 2y = 19 x + 3y =

14 (1.-17) (-1, 17) (-17, 1) (17,-1)​
Mathematics
1 answer:
masha68 [24]3 years ago
4 0

Answer:

D. (17,-1)

Step-by-step explanation:

We'll start by canceling out x. To do so, multiple the first equation by -1

-1( x - 2y)=( 19 )(-1)

This gives us:

-x +2y = -19

x + 3y = 14

Add the equations together:

→ 5y = -15

→ y = -1

Plug in y = -1 into an equation:

→ x + 3(-1) = 14

→ x - 3 = 14

→ x = 17

(17,-1)

Hope this helps!

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Citrus2011 [14]

Answer:

y=-2

Step-by-step explanation:

4 0
3 years ago
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Find the area of the triangle
Helga [31]

Answer:

The answer is

\huge \boxed{54 \:  \:  {units}^{2} }

Step-by-step explanation:

Area of a triangle is given by

A =  \frac{1}{2}  \times base \times height \\

From the question

base = 18

height = 6

So we have

A =  \frac{1}{2}  \times 18 \times 6 \\  = 9 \times 6 \\  = 54 \:  \:  \:  \:  \:

We have the final answer as

<h3>54 units²</h3>

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3 0
3 years ago
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Simplify 4/(√5+ √2) - 3/(√5- √2)​
MakcuM [25]

Step-by-step explanation:

\frac{4}{ \sqrt{5} +   \sqrt{2}}  -  \frac{3}{ \sqrt{5} -  \sqrt{2}  }  =  \\  =  \frac{4( \sqrt{5}  -  \sqrt{2} ) - 3( \sqrt{5} +  \sqrt{2} ) }{( \sqrt{5}  +  \sqrt{2}  )\times ( \sqrt{5}  -  \sqrt{2} )}  =  \\  =  \frac{4 \sqrt{5} - 4 \sqrt{2}  - 3 \sqrt{5} - 3 \sqrt{2}   }{5 -  \sqrt{10}  +  \sqrt{10} - 2 }  =  \\  =  \frac{ \sqrt{5}  - 7 \sqrt{2} }{3}

8 0
2 years ago
4+2(7)= <br><br> 62+8×3= <br><br> 3(2+5)−5(3)+8= <br><br> 24−6+12÷2×3=
Temka [501]

4+2(7)= 18

62+8x3= 86

3(2+5)-5(3)+8= 14

24-6+12÷2x3= 36

Hope this helps you! :D

3 0
3 years ago
Liam has to fill a hole in the ground that is 24 inches deep. He fills the hole at a rate of 6 inches in 30 minutes. Write a fun
kupik [55]

Answer:

The function that models the depth of the hole in feet over time in hours is h(t) = 24 - 12\cdot t.

Step-by-step explanation:

According to the statement, the variable to be modelled is the depth of the hole, which decreases whereas is filled. Under the assumption that the hole is filled at constant rate, we obtain the following expression:

h(t) = h_{o}-\frac{\Delta h}{\Delta t}\cdot t (1)

Where:

h(t) - Current depth of the hole, measured in inches.

h_{o} - Initial depth of the hole, measured in inches.

\Delta h - Filled level, measured in inches.

\Delta t - Filling time, measured in hours.

t - Time, measured in hours.

If we know that h_{o} = 24\,in, \Delta h = 6\,in and \Delta t = 0.5\,h, then the function that models the depth of the hole is:

h(t) = 24 - 12\cdot t

The function that models the depth of the hole in feet over time in hours is h(t) = 24 - 12\cdot t.

6 0
3 years ago
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