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Vedmedyk [2.9K]
2 years ago
8

The first population is currently 124,900. if the population doubles every 25 years, what will the population be 100 years from

now
​
Mathematics
2 answers:
kvv77 [185]2 years ago
8 0

Answer:

It should be 1,998,400

Step-by-step explanation:

124,900 x 2 is 249,800

249,800 x 2 is 499,600

499,600 x 2 is 999,200

999,200 x 2 is 1,998,400

Hope this helps

Tatiana [17]2 years ago
5 0
You will divide 25 into 100 which then you would get 4 then you should multiply 124,900 times 4 which equals = 499,600
Please work this out it is really easy. I hope this helps
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Answer:

y = -¼│x − 5│+ 3

Step-by-step explanation:

y = a│x − h│+ k

(h, k) is the vertex of the absolute value graph.  In this case, it's (5, 3).

y = a│x − 5│+ 3

One point on the graph is (1, 2).  Plug in to find the value of a.

2 = a│1 − 5│+ 3

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Therefore, the graph is:

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If segment LN is congruent to segment NP and ∠1 ≅ ∠2, prove that ∠NLO ≅ ∠NPM:
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These data can be approximated quite well by a N(3.4, 3.1) model. Economists become alarmed when productivity decreases. Accordi
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Answer:

First part

P(X< 3.4-0.6*3.1) = P(X

And for this case we can use the z score formula given by:

z = \frac{x- \mu}{\sigma}

And using this formula we got:

P(X

And we can use the normal standard table or excel and we got:

P(Z

Second part

For the other part of the question we want to find the following probability:

P(-1.715

And using the score we got:

P(-1.715

And we can find this probability with this difference:

P(-1.65< Z< 1.210)=P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the data of a population, and for this case we know the distribution for X is given by:

X \sim N(3.4,3.1)  

Where \mu=3.4 and \sigma=3.1

First part

And for this case we want this probability:

P(X< 3.4-0.6*3.1) = P(X

And for this case we can use the z score formula given by:

z = \frac{x- \mu}{\sigma}

And using this formula we got:

P(X

And we can use the normal standard table or excel and we got:

P(Z

Second part

For the other part of the question we want to find the following probability:

P(-1.715

And using the score we got:

P(-1.715

And we can find this probability with this difference:

P(-1.65< Z< 1.210)=P(Z

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3 years ago
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