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—————
Solve the initial value problem:
dy
——— = 2xy², y = 2, when x = – 1.
dx
Separate the variables in the equation above:
Integrate both sides:
Take the reciprocal of both sides, and then you have
In order to find the value of C₁ , just plug in the equation above those known values for x and y, then solve it for C₁:
y = 2, when x = – 1. So,
Substitute that for C₁ into (i), and you have
So y(– 2) is
I hope this helps. =)
Tags: <em>ordinary differential equation ode integration separable variables initial value problem differential integral calculus</em>
—————
Solve the initial value problem:
dy
——— = 2xy², y = 2, when x = – 1.
dx
Separate the variables in the equation above:
Integrate both sides:
Take the reciprocal of both sides, and then you have
In order to find the value of C₁ , just plug in the equation above those known values for x and y, then solve it for C₁:
y = 2, when x = – 1. So,
Substitute that for C₁ into (i), and you have
So y(– 2) is
I hope this helps. =)
Tags: <em>ordinary differential equation ode integration separable variables initial value problem differential integral calculus</em>