Among ¹⁴⁰₅₅Cs and ¹³³₅₅Cs, <u>¹³³₅₅Cs</u> is more stable.
<h3>Briefly explained</h3>
Let's review the criteria that are used to determine a stable isotope. A stable isotope will have more neutrons than protons with a neutron to proton ratio somewhere between one and 1.52 On the high atomic number, we're up to 152 at low atomic numbers were closer to one. More stable isotopes have an even number of protons. And neutrons.
And stable isotopes have their proton or neutron number equal to one of these magic numbers. So if we have season one, It has 85 Protons are start 85 neutrons And 55 protons. So we have a neutron to proton ratio of 155 for CCM 1 33. We have 78 neutrons and 55 protons for a neutron to proton ratio of 1.42. 155 is a little high for z equal to 55.
Both of these are also odd. So ¹⁴⁰₅₅Cs is the least stable. ¹³³₅₅Cs is the most stable.
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As we know that neutralization reaction is a reaction in which base react with acid to form salt and water.
When Potassium Hydroxide reacts with Sulphuric Acid, it forms Potassium Sulphate and Water.
As a result of neutralization reaction, Potassium Sulphate and Water is formed.
2KOH + H2SO4 ----> K2SO4 + 2H2O
Here, K2SO4 is found in aqueous medium in neutralization reaction. It is a neutral salt.
The half-life of polonium-210, given that it decays from 98.3 micrograms to 12.3 micrograms in 414 days is 138 days
<h3>How to determine the number of half-lives </h3>
- Original amount (N₀) = 98.3 micrograms
- Amount remaining (N) = 12.3 micrograms
- Number of half-lives (n) =?
2ⁿ = N₀ / N
2ⁿ = 98.3 / 12.3
2ⁿ = 8
2ⁿ = 2³
n = 3
<h3>How to determine the half life </h3>
- Number of half-lives (n) = 3
- Time (t) = 414 days
- Half-life (t½) = ?
t½ = t / n
t½ = 414 / 3
t½ = 138 days
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Answer:
42.3%
Explanation:
By the reaction given the stoichiometry between MnO₄⁻ and Fe⁺² is 1 mol of MnO₄⁻ to 5 moles of Fe⁺². When KMnO₄ dissolves, it forms the same amount of K⁺ and MnO₄⁻ (1:1:1), so the number of moles of MnO₄⁻ used is:
n = Volume*concentration
n = 0.0216 L * 0.102 mol/L
n = 2.20x10⁻³ mol
1 mol of MnO₄⁻ -------------------- 5 moles of Fe⁺
2.20x10⁻³ mol ---------------------- x
By a simple direct three rule
x = 0.011 mole
The molar mass of iron is 55.8 g/mol. The mass is the molar mass multiplied by the number of moles, thus:
m = 55.8*0.011
m = 0.614 g
Then, the percent of iron in the ore is:
(mass of iron/ mass of ore) *100%
(0.614/1.45)*100%
42.3%
Explanation:
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