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3 years ago

What happens when Potassium Hydroxide reacts with Sulphuric Acid?

Chemistry

2 answers:

Ede4ka [16]3 years ago

5 0

As we know that neutralization reaction is a reaction in which base react with acid to form salt and water.

When Potassium Hydroxide reacts with Sulphuric Acid, it forms Potassium Sulphate and Water.

As a result of neutralization reaction, Potassium Sulphate and Water is formed.

2KOH + H2SO4 ----> K2SO4 + 2H2O

Here, K2SO4 is found in aqueous medium in neutralization reaction. It is a neutral salt.

4vir4ik [10]3 years ago

3 0

Here is your answer

We know that when an acid reacts with base, salt and water is formed.

This reaction is called Neutralisation reaction.

So,

2KOH + H2SO4 -> K2SO4(aq) + 2H2O

Reaction of Potassium Hydroxide with Sulphuric acid gives Potassium sulphate and water as product.

HOPE IT IS USEFUL

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In a study of the conversion of methane to other fuels, a chemical engineer mixes gaseous methane and gaseous water in a 0.778 L

sergejj [24]

Answer:

the water concentration at equilibrium is

⇒ [ H2O(g) ] = 0.0510 mol/L

Explanation:

CH4(g) + H2O(g) ↔ CO(g) + 3H2(g)

∴ Kc = ( [ CO(g) ] * [ H2 ]³ ) / ( [ CH4(g) ] * [ H2O(g) ] ) = 0,30

equilibrium:

⇒ [ CO(g) ] = 0.206 mol / 0.778 L = 0.2648 mol/L

⇒ [ H2(g) ] = 0.187 mol / 0.778 L = 0.2404 mol/L

⇒ [ CH4(g) ] = 0.187 mol / 0.778 L = 0.2404 mol/L

replacing in Kc:

⇒ ((0.2648) * (0.2404)³) / ([ H2O(g) ] * 0.2404 ) = 0.30

⇒ 0.0721 [ H2O(g) ] = 3.679 E-3

⇒ [ H2O(g) ] = 0.0510 mol/L

7 0

3 years ago

As with other ionic compounds, potassium bromate, KBrO3, dissociates into ions when it dissolves in water. If 13.8 g of KBrO3 is

chubhunter [2.5K]

Answer:

ΔH of dissociation is 38,0 kJ/mol

Explanation:

The dissociation reaction of KBrO₃ is:

KBrO₃ → K⁺ + BrO₃⁻ 

This dissolution consume heat that is evidenced with the decrease in water temperature.

The heat consumed is:

q = CΔTm

Where C is specific heat of water (4,186 J/mol°C)

ΔT is the temperature changing (18,0°C - 13,0°C = 5,0°C)

And m is mass of water (150,0 mL ≈ 150,0 g)

Replacing, heat consumed is:

q = 3139,5 J ≡ 3,14 kJ

13,8 g of KBrO₃ are:

13,8 g×(1mol/167g) = 0,0826 moles

Thus, ΔH of dissociation is:

3,14kJ / 0,0826mol = 38,0 kJ/mol

I hope it helps!

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3 years ago

Is syrup a compound or solution

S_A_V [24]

Answer:

Syrup is a mixture of thick sticky liquid consisting of a concentrated solution of sugar and water with or without the addition of a flavoring agent or medicinal substance.

Explanation:

so compound

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3 years ago

Which reactants would lead to a spontaneous reaction?

balandron [24]

Answer: Option (b) is the correct answer.

Explanation:

The elements which have excess or deficiency of electrons will react readily.

Atomic number of Mn is 25 and electronic configuration of $Mn^{2+}$ is [Ar] $4s^{0}3d^{5}$ . This configuration is stable.

Atomic number of Cr is 24 and electronic configuration of $Cr$ is [Ar] $4s^{1}3d^{5}$ . This configuration is not stable.

Atomic number of Fe is 26 and electronic configuration of $Fe$ is [Ar] $4s^{2}3d^{6}$ . This configuration is stable.

Atomic number of Cu is 29 and electronic configuration of $Cu^{2+}$ is [Ar] $4s^{0}3d^{9}$ . This configuration is not stable.

Atomic number of Al is 13 and electronic configuration of Al is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}$ . This configuration is not stable.

Atomic number of Ba is 56 and electronic configuration of $Ba^{2+}$ is [Kr] $4d^{10}5s^{2}5p^{6}$ . This configuration is stable.

Atomic number of Mg is 12 and electronic configuration of $Mg^{2+}$ is $1s^{2}2s^{2}2p^{6}$ . This configuration is stable.

Atomic number of Sn is 50 and electronic configuration of Sn is [Kr] $4d^{10}5s^{2}5p^{2}$ . This configuration is stable.

Thus, we can conclude that out of the given options, only Fe and $Cu^{2+}$ reactants would lead to a spontaneous reaction as they have incomplete sub-shells. Therefore, in order to gain stability they will readily react.

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3 years ago

How many atoms in 2.8 mol of neon? (show working)

ioda

To find the amount of atoms in a mole you will use Avragadro's constant. So 2.8 x 6.02 x 10^23 (2.8x 6.02 ten to the power of 23)
2.8x 6.02 10^23

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3 years ago

What happens when Potassium Hydroxide reacts with Sulphuric Acid?​

What happens when Potassium Hydroxide reacts with Sulphuric Acid?