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RoseWind [281]
3 years ago
14

Is this statement true or false 8/15 < 3/5

Mathematics
2 answers:
gayaneshka [121]3 years ago
7 0
TRUE because 8/15 = 0.53 which is less than 3/5 = 0.60
nikitadnepr [17]3 years ago
3 0

Answer:

True

Step-by-step explanation:

To get common denominators, you must multiply 3/5 by 3

3*3=9

9/15>8/15 (meaning 3/5 is greater than 8/15)

Hope this helps! :)

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Who can solve this <br>2xy if x=5 and y=-3​
Softa [21]

Answer:

-30

Step-by-step explanation:

2*5 is 10

10*-3 is -30

8 0
3 years ago
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jason went to an arcade to play video games. he paid $2 for every 11 tokens he bought. he spent a total of $16 on tokens. which
SVEN [57.7K]

Answer:

D

Step-by-step explanation:

Since there are two types of values here: tokens and dollars, we will need to use the same value across numerators and denominators in the ratio.

Choice D has 11 tokens over $2 equals to t tokens over $16. In both fractions the numerator is tokens and denominator is dollars.

6 0
3 years ago
Find the value of X<br> please help!
denis23 [38]

Answer:

Step-by-step explanation:

So the first thing to do is get the number of angles inside this pentagon, which is 540 degrees. One way to do this is that you know a pentagon is formed of 3 triangles and since there are 180 degrees in a triangle, 3x180=540

Then it is algebra

540=91+125+92+(3x-5)+(4x-8)

Simplify what you can and collect like terms

540=308+3x-5+4x-8

540=308+7x-13

Then move everything over to the one side so that the variable is isolated

540-308+13=7x

245=7x

242/7=x

35=x

5 0
2 years ago
The intercepts of the circle (x-1)^2 + (y-2)^2 = 10 are ?
IRISSAK [1]

y-intercept:  Let x = 0 and solve for y:

(x-1)^2 + (y-2)^2 = 10 => (-1)^2 + y^2 - 4y + 4) = 10

                                =>  1 + y^2 - 4y + 4 = 10, or   y^2 - 4y  -5 = 0

                                The solutions of this quadratic are y = 5 and y = -1.

                                Thus, the y-intercepts are (0, 5) and (0, -1).

Now find the x-intercepts:  Let y = 0 and solve the resulting equation for x:

(x-1)^2 = 10 - (-2)^2, or (x-1)^2 = 10 - 4 = 6.

Taking the sqrt of both sides, x - 1 = plus or minus sqrt(6), or:

                                                  x = 1 +√6 and x = 1 - √6, so that the x-intercepts

                                                  are (1+√6, 0) and (1-√6, 0).

8 0
3 years ago
Use multiplication or division of power series to find the first three nonzero terms in the Maclaurin series for each function.
Lunna [17]

Answer:

The first three nonzero terms in the Maclaurin series is

\mathbf{ 5e^{-x^2} cos (4x)  }= \mathbf{ 5 ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }

Step-by-step explanation:

GIven that:

f(x) = 5e^{-x^2} cos (4x)

The Maclaurin series of cos x can be expressed as :

\mathtt{cos \ x = \sum \limits ^{\infty}_{n =0} (-1)^n \dfrac{x^{2n}}{2!} = 1 - \dfrac{x^2}{2!}+\dfrac{x^4}{4!}-\dfrac{x^6}{6!}+...  \ \ \ (1)}

\mathtt{e^{-2^x} = \sum \limits^{\infty}_{n=0}  \ \dfrac{(-x^2)^n}{n!} = \sum \limits ^{\infty}_{n=0} (-1)^n \ \dfrac{x^{2n} }{x!} = 1 -x^2+ \dfrac{x^4}{2!}  -\dfrac{x^6}{3!}+... \ \ \  (2)}

From equation(1), substituting x with (4x), Then:

\mathtt{cos (4x) = 1 - \dfrac{(4x)^2}{2!}+ \dfrac{(4x)^4}{4!}- \dfrac{(4x)^6}{6!}+...}

The first three terms of cos (4x) is:

\mathtt{cos (4x) = 1 - \dfrac{(4x)^2}{2!}+ \dfrac{(4x)^4}{4!}-...}

\mathtt{cos (4x) = 1 - \dfrac{16x^2}{2}+ \dfrac{256x^4}{24}-...}

\mathtt{cos (4x) = 1 - 8x^2+ \dfrac{32x^4}{3}-... \ \ \ (3)}

Multiplying equation (2) with (3); we have :

\mathtt{ e^{-x^2} cos (4x) = ( 1- x^2 + \dfrac{x^4}{2!} ) \times ( 1 - 8x^2 + \dfrac{32 \ x^4}{3} ) }

\mathtt{ e^{-x^2} cos (4x) = ( 1+ (-8-1)x^2 + (\dfrac{32}{3} + \dfrac{1}{2}+8)x^4 + ...) }

\mathtt{ e^{-x^2} cos (4x) = ( 1 -9x^2 + (\dfrac{64+3+48}{6})x^4+ ...) }

\mathtt{ e^{-x^2} cos (4x) = ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }

Finally , multiplying 5 with \mathtt{ e^{-x^2} cos (4x) } ; we have:

The first three nonzero terms in the Maclaurin series is

\mathbf{ 5e^{-x^2} cos (4x)  }= \mathbf{ 5 ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }

7 0
3 years ago
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