Rotation will not map the preimage ABC onto the image A'B'C'
Following transformations on Triangle ABC will result in the Triangle A'B'C'
a) Reflection the triangle across x-axis
b) Shift towards Right by 2 units
c) Shift upwards by 6 units
In Triangle ABC, the coordinates of the vertices are:
A (1,9)
B (3, 12)
C (4, 4)
In Triangle A'B'C, the coordinates of the vertices are:
A' (3, -3)
B' (5, -6)
C' (6, 2)
First consider point A of Triangle ABC.
Coordinate of A are (1, 9). If we reflect it across x-axis the coordinate of new point will be (1, -9). Moving it 2 units to right will result in the point (3, -9). Moving it 6 units up will result in the point (3,-3) which are the coordinates of point A'.
Coordinates of B are (3,12). Reflecting it across x-axis, we get the new point (3, -12). Moving 2 units towards right, the point is translated to (5, -12). Moving 6 units up we get the point (5, -6), which are the coordinate of B'.
The same way C is translated to C'.
Thus the set of transformations applied on ABC to get A'B'C' are:
a) Reflection the triangle across x-axis
b) Shift towards Right by 2 units
c) Shift upwards by 6 units
Answer:
these are (-4,-1) and (8,8) because
-1=-4*3/4+2
-1=-3=2
-1=-1
8=24/4+2
8=8
Step-by-step explanation:
Midpoint of the segment connecting the points (5,3)and (7,-2)is (6,1/2)
Answer:
Real part = 3 & imaginary part = 1
2) 4 + 7i - 8 = 4 -8 + 7i
= -4 + 7i
Real part = -4 & imaginary part = 7
Real part = -2 & imaginary part = -5
b) 1) 6 + 4i
2) -12+ 5i
3) 5-14i
