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Vikki [24]
3 years ago
5

I will rate brainly if you answer this The number of weekly social media posts varies directly with the square root of the poste

r’s age and inversely with the cube root of the poster’s income. If a 16-year-old person who earns $8,000 makes 64 posts in a week, what is the value of k?
Mathematics
2 answers:
juin [17]3 years ago
6 0
K=320.

If a=age, m=income, and n=number of weekly posts:
The relationship can be modeled by
n=k * sqrt(a) / cbrt(m). sqrt(a) is in the numerator because it is directly proportional to n and cbrt(m) is in the denominator because it is inversely proportional to n.
Plugging in the given values, n=64, a=16, m=8000, 64=k* sqrt(16) / cbrt(8000). sqrt(16)=4, and cbrt(8000)=20, so 64=4k/20=k/5. So k=64*5= 320.
ryzh [129]3 years ago
5 0

Answer:

\large \boxed{\sf \bf \ \ k=320 \ \ }

Step-by-step explanation:

Hello,

The number of weekly social media posts varies directly with the square root of the poster’s age and inversely with the cube root of the poster’s income.

If a 16-year-old person who earns $8,000 makes 64 posts in a week, what is the value of k?

64=\dfrac{\sqrt{16}}{\sqrt[3]{8000}}\cdot k=\dfrac{4}{20}\cdot k=\dfrac{1}{5}\cdot k=0.2\cdot k\\\\k=64*5=320

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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Daniel bought four bags of potatoes. The weight of the first bag was 2.6 pounds. The second bag weighed 0.4 pound less than twic
ipn [44]

Answer:

Average weight of the bags of potatoes is 3.8 pounds.

Step-by-step explanation:

Given:

Weight of the first bag, W_{1}=2.6 pounds.

Weight of the second bag is 0.4 pounds less than twice the weight of first bag. This means,

W_{2}=2W_{1}-0.4=2(2.6)-0.4=5.2-0.4=4.8\textrm{ pounds}

Weight of the third bag is 0.6 pounds more than that of the first bag. This means,

W_{3}=W_{1}+0.6=2.6+0.6=3.2\textrm{ pounds}

Weight of the fourth bag is 0.3 pounds less than that of the second bag. This means,

W_{4}=W_{2}-0.3=4.8-0.3=4.5\textrm{ pounds}

Therefore, the average weight of the bags of potatoes is given as the sum of all the weights and then divide the sum by 4. Therefore,

W_{average}=\frac{W_{1}+W_{2}+W_{3}+W_{4}}{4}=\frac{2.6+4.8+3.2+4.5}{2}=\frac{15.1}{4}=3.775\approx 3.8

Therefore, average weight of the bags of potatoes is 3.8 pounds.

8 0
3 years ago
Calculate the product of 8/15, 6/5, and 1/3. 
Mariulka [41]
\frac{8}{15} * \frac{6}{5} * \frac{1}{3}

First, I would multiply the last two fractions because they're smaller and easier to work with:

\frac{8}{15} * \frac{6}{5} * \frac{1}{3} = \frac{8}{15} * \frac{6}{15}

Now that we've simplified it, we could multiply these terms and simplify.  An easier method, however, would be to cancel out any common factors among the numerators and denominators before multiplying:

\frac{8}{15} * \frac{6}{15} = \frac{8}{5} * \frac{2}{15}

We can now multiply these terms:

\frac{8}{5} * \frac{2}{15} =  \frac{16}{75}

The <span>product of 8/15, 6/5, and 1/3 is B, 16/75.</span>
5 0
3 years ago
Write an exponential function to model the situation.A population of 300 animals decreased at an annual rate of 22%
erastovalidia [21]

Answer:

y = 300(0.78)^x

Step-by-step explanation:

x is the number of years. y is the population after x years.

Each year, the population decreases by 22%, since 100% - 22% = 78%, and 78% = 0.78, each year, the population is 0.78 of the previous year's population.

year zero: y = 300

year 1: y = 300 * 0.78 = 300 * (0.78)^1

year 2: y = (300 * 0.78) * 0.78 = 300 * (0.78)^2

year 3: y = ((300 * 0.78) * 0.78) * 0.78 = 300 * (0.78)^3

year x: y = 300(0.78)^x

4 0
3 years ago
Select the correct answer.<br> Which graph shows a function and its inverse?
Anit [1.1K]

Answer:

first graph shows the function and it's inverse

8 0
3 years ago
Evaluate the exponential expression (−2)6. Question 6 options: −12 12 −64 64
OlgaM077 [116]

Answer:

64

Step-by-step explanation:

(-2) ^6

This is -2 multiplied by itself 6 times

-2 * -2 *-2 * -2* -2 *-2

64

7 0
3 years ago
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