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3 years ago

10

Shown above is the graph of the differentiable function f, along with the line tangent to the graph of f at x=2. What is the val

ue of f′(2) ?

1 answer:

Zielflug [23.3K]3 years ago

5 0

f'(2) means "the slope of the tangent line to y=f(x) when x=2".

Since that tangent line is drawn, this is really asking, "What's the slope of that line?"

So, what's the rise/run for that line?

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Mistake in Line 2 : Was in the determining the values for a ,b,c

Mistake in Line 4 : Not taking the square roots of both sides.

Step-by-step explanation:

${a}^{2} + {b}^{2} = {c}^{2}$

First Mistake : Line 2

$a = x \\ b = 6 \\ c = 10$

Second Mistake : Line 4

$136 = {x}^{2} \\ not \\ 136 = x$

Correct Solution :

${x}^{2} + {6}^{2} = {10}^{2} \\ {x}^{2} = {10}^{2} - {6}^{2} \\ {x}^{2} = 100 - 36 \\$

${x}^{2} = 64 \\ \sqrt{ {x}^{2} } = \sqrt{64} \\ x = 6$

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