We know that
The Intersecting Chord Theorem, established that "<span>When two chords intersect each other inside a circle, the products of their segments are equal."
</span>so
(n+2)*16=(n+8)*8
16n+32=8n+64
16n-8n=64-32
8n=32
n=32/8
n=4
the answer is
n=4
To solve this problem, you need to do it in this order: PEMDAS
(Parentheses, Exponent, Multiplication, Division, Addition, Subtraction)
2 × 4 ÷ 6(8 × 3) - 6 = Y First simplify inside the ( ), and multiply 8 by 3
2 × 4 ÷ 6(24) - 6 = Y Now multiply 6 and 24
2 × 4 ÷ 144 - 6 = Y Multiply 2 and 4
8 ÷ 144 - 6 = Y Divide 8 and 144
18 - 6 = Y Subtract 18 and 6
12 = Y
Answer:linear
Step-by-step explanation:
Answer:
D. 10
Step-by-step explanation:
The chord is bisected as shown by the perpendicular lines and right angle, so both segments are 6.
Draw a radius from the center to the end of the chord to create a right triangle. 8 and 6 are the legs, use pythagorean theorem to find the length of the segment you drew because its the hypotenuse.
8^2+6^2=x^2
64+36
100
square root of 100 is 10
So, 10 is the length of the segment. Both the x segment and the 10 segment are radii because they are draw from the center to a point on the circle.
They are equal.
x=10
