The denominator of the raised fraction is what goes on the outside of the square root. So if you had 2 raised to 1/3, you'd put the 3 raised outside to the left of the radical and the 2 inside. They give the same answer, so if you know one, you can always play with the other until you get the same answer. My teacher told us in Calculus a funny/weird way to remember it is the "bottom (of the raised fraction) goes in the crack (of the radical)." Does this help??
Answer:
50 increased by 30% is 65
Step-by-step explanation:
'Percent (%)' means 'out of one hundred':
p% = p 'out of one hundred',
p% is read p 'percent',
p% = p/100 = p ÷ 100.
30% = 30/100 = 30 ÷ 100 = 0.3.
100% = 100/100 = 100 ÷ 100 = 1.
Percentage increase = 30% × 50
New value = 50 + Percentage increase
Calculate
New value =
50 + Percentage increase =
50 + (30% × 50) =
50 + 30% × 50 =
(1 + 30%) × 50 =
(100% + 30%) × 50 =
130% × 50 =
130 ÷ 100 × 50 =
130 × 50 ÷ 100 =
6,500 ÷ 100 =
65
Or just find 30% of 50 (15) and add that

<h3><u>Given </u><u>:</u><u>-</u></h3>
- We have given the coordinates of the triangle PQR that is P(-4,6) , Q(6,1) and R(2,9)
<h3><u>To</u><u> </u><u>Find </u><u>:</u><u>-</u></h3>
- <u>We </u><u>have </u><u>to </u><u>calculate </u><u>the </u><u>length </u><u>of </u><u>the </u><u>sides </u><u>of </u><u>given </u><u>triangle </u><u>and </u><u>also </u><u>we </u><u>have </u><u>to </u><u>determine </u><u>whether </u><u>it </u><u>is </u><u>right </u><u>angled </u><u>triangle </u><u>or </u><u>not </u>
<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u></h3>
<u>Here</u><u>, </u><u> </u><u>we </u><u>have </u>
- Coordinates of P =( x1 = -4 , y1 = 6)
- Coordinates of Q = ( x2 = 6 , y2 = 1 )
- Coordinates of R = ( x3 = 2 , y3 = 9 )
<u>By </u><u>using </u><u>distance </u><u>formula </u>

<u>Subsitute </u><u>the </u><u>required </u><u>values </u><u>in </u><u>the </u><u>above </u><u>formula </u><u>:</u><u>-</u>
Length of side PQ






Length of QR





Length of RP





<h3><u>Now</u><u>, </u></h3>
We have to determine whether the triangle PQR is right angled triangle
<h3>Therefore, </h3>
<u>By </u><u>using </u><u>Pythagoras </u><u>theorem </u><u>:</u><u>-</u>
- Pythagoras theorem states that the sum of squares of two sides that is sum of squares of 2 smaller sides of triangle is equal to the square of hypotenuse that is square of longest side of triangle
<u>That </u><u>is</u><u>, </u>

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>,</u>


<u>From </u><u>above </u><u>we </u><u>can </u><u>conclude </u><u>that</u><u>, </u>
- The triangle PQR is not a right angled triangle because 205 ≠ 45 .
There were 16 boys
-5:4, 10:8, 15:12, 20:16
-20:16 is 20+16=36
-20 were girls and 16 were boys
Answer:
B
Step-by-step explanation:
Given a function of a parabola (quadratic) in the form f(x) = x^2, we have a translated function as:
g(x) = a(x-b)^2
Where
- a is the vertical compression or stretch. If a > 1, it is a vertical stretch and if 0 < a < 1, it is a vertical compression.
- b is the horizontal translation b units to the right
The function given is p(x) = 3(x-8)^2
So it means that it is a vertical stretch with a factor 3 and the graph is shifted horizontally 8 units right
the correct answer is B